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konstantin123 [22]

4 years ago

6

A chemical reaction has the equation 2AgNO3 (aq) + Zn (s) —> 2Ag (s) + Zn(NO3)2 (aq). What type of reaction occurs between Ag

No3 and Zn?
A. Synthesis
B. Double displacement
C. Decomposition
D. Single displacement

1 answer:

Softa [21]4 years ago

4 0

This is a single displacement reaction. D

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As gravity makes an object fall down toward the ground,______ energey becomes kinetics energy

Anton [14]

Answer:

Explanation:

Potential energy is the energy possessed by an object due to its position. For example, when the ball starts to move from its resting position then the ball gains kinetic energy. Thus, as gravity makes an object fall down toward the ground, potential energy becomes kinetic energy.

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3 years ago

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When 42.5 g of benzamide (C7H7NO) are dissolved in 500 g of a certain mystery liquid X, the freezing point of the solution is 6.

LuckyWell [14K]

Answer:

21.3g of Fe(NO₃)₃ are required to produce the same depression in freezing point of solution.

Explanation:

Freezing point depression is a colligative property which indicates, in determined mixture, the freezing point of solution is lower that the freezing point of the solvent, according the amount of solute.

Formula is: ΔT = Kf . m . i

Kf is the cryoscopic constant, which is particular for each solvent. We do not have that data, so we need to find it out in order to solve the question:

ΔT = Freezing point of pure solvent - Freezing point of solution.

This data is known → 6.40°C

m, means molality, moles of solute in 1kg of solvent. Let's get the moles of benzamide: 42.5 g . 1mol / 121g = 0.351 moles

m = 0.351 mol / 0.5kg = 0.702 m

As benzamide is an organic compound i, = 1. i are the number of ions dissolved in solution. Let's find out Kf:

6.40°C = Kf . 0.702 m . 1

6.40°C /0.702m = 9.11 °C/m.

Let's go to the next question.

ΔT is the same → 6.40°C

But this is, an inorganic salt, a ionic salt: Fe(NO₃)₃ → 1Fe³⁺ + 3NO₃⁻

For this case, we have 1 mol of Iron(III) and 3 nitrates, so i = 4

Let's replace data: 6.40°C = 9.11 °C/m . m . 4

6.40°C / (9.11 m/°C . 4) = 0.176 m

This data represents that, in 1 kg of solvent we have 0.176 moles of nitrate.

Mass of solvent X required in this case is 0.500 kg, so, the moles that are contained are: 0.500 kg . 0.176 mol/kg = 0.088 mol

Let's determine the mass of salt: 0.088 mol . 241.85g /1mol = 21.3 g

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3 years ago

Which substance can be broken down by chemical means?

Gnoma [55]

Answer:

Compounds

Compounds – pure substances that are the unions of two or more elements. They can be broken into simpler substances by chemical means.

Explanation:

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3 years ago

What is the chemical formula of the salt produced by the neutralization of potassium hydroxide with sulfuric acid? A. KSO3 B. K2

Lunna [17]

Answer : The correct option is, (C) $K_2SO_4$

Explanation :

Neutralization reaction : It is a type of chemical reaction in which an acid react with a base to give salt and water as a product that means it reacts to give a neutral solution.

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

When potassium hydroxide react with sulfuric acid then it react to give potassium sulfate (salt)and water as a product.

The balanced chemical reaction will be:

$2KOH+H_2SO_4\rightarrow K_2SO_4+2H_2O$

The species present on the left side of the right arrow is the reactant and the species present on the right side of the right arrow is the product.

In the balanced chemical reaction,

$KOH$ and $H_2SO_4$ are reactants.

$K_2SO_4$ and $H_2O$ are products.

Hence, the chemical formula of the salt produced by the neutralization of potassium hydroxide with sulfuric acid is, $K_2SO_4$

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3 years ago

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The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine

Viefleur [7K]

Answer:

16.2 J

Explanation:

Step 1: Given data

Specific heat of liquid bromine (c): 0.226 J/g.K

Volume of bromine (V): 10.0 mL

Initial temperature: 25.00 °C

Final temperature: 27.30 °C

Density of bromine (ρ): 3.12 g/mL

Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

ρ = m/V

m = ρ × V

m = 3.12 g/mL × 10.0 mL

m = 31.2 g

Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

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3 years ago