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ludmilkaskok [199]
3 years ago
6

I need help on 6a and 6b

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0
You have to use Avogadro's number which is 6.02×10²³ which tells you the number of particles in 1 mole of a sample.

6a) 2mol Fe²⁺
(2mol Fe²⁺)×(6.02×10²³ions/mol)=<span>1.2×10²⁴ ions of Fe²⁺

</span>6b) 4.5mol BCl₃
(4.5mol BCl₃)×(6.02×10²³ molecules/mol)=2.7×10²⁴molecules of BCl₃

I hope this helps.  Let me know if anything is unclear.
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Correct each of the following names:<br> (c) MgCr₂O₇ is magnesium dichromium heptaoxide
zhenek [66]

Magnesium dichromate is the correct name of the compound MgCr₂O₇.

<h3>What is Molecular Formula ?</h3>

The chemical formula that gives total number of atoms of each element in one molecule of a compound is called Molecular Formula.

<h3>What is Oxidation State ?</h3>

Oxidation state is also known as oxidation number. It is defined as the atom is equal to the total number of electrons which have been removed from the element in order to form chemical bond with other atom.

Magnesium dichromate contains the Magnesium ion and chromate ions. Magnesium ion is represented as Mg⁺². Oxidation state of magnesium is +2. The chromate ion is represented as Cr₂O₇⁻². Oxidation state of chromate ion is -2.

Thus from the above conclusion we can say that The correct name of the compound MgCr₂O₇ is Magnesium dichromate.

Learn more about the Oxidation State here: brainly.com/question/8990767

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8 0
2 years ago
Given: 36.7 grams of CaF2 is added to 300 mL water. Find molarity?
BigorU [14]
<h3>Answer:</h3>

2 M

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Unit 0</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution
<h3>Explanation:</h3>

<u>Step 1: Define</u>

36.7 g CaF₂

300 mL H₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol

1000 mL = 1 L

<u>Step 3: Convert</u>

<em>Solute</em>

  1. Set up:                               \displaystyle 36.7 \ g \ CaF_2(\frac{1 \ mol \ CaF_2}{78.08 \ g \ CaF_2})
  2. Multiply:                             \displaystyle 0.470031 \ mol \ CaF_2

<em>Solution</em>

  1. Set up:                              \displaystyle 300 \ mL \ H_2O(\frac{1 \ L \ H_2O}{1000 \ mL \ H_2O})
  2. Multiply:                            \displaystyle 0.3 \ L \ H_2O

<u>Step 4: Find Molarity</u>

  1. Substitute [M]:                    \displaystyle x \ M = \frac{0.470031 \ mol \ CaF_2}{.3 \ L \ H_2O}
  2. Divide:                                \displaystyle x = 1.56677 \ M

<u>Step 5: Check</u>

<em>Follow sig fig rules and round.</em> <em>We are given 1 sig fig as our lowest.</em>

1.56677 M ≈ 2 M

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Answer:

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Explanation:

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