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3 years ago

The radio of 2,787 to 1,750 is ____

Mathematics

1 answer:

pishuonlain [190]3 years ago

3 0

Answer:

1.59

Step-by-step explanation:

Divide 2,787 by 1,750

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2 years ago

Why might a mattress store choose to advertise new mattresses, worth $1,000, as $50 per week for 22 weeks?

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By doing so, they provide the illusion that the payments are cheaper then 1000 dollars, because 50 looks very small, when in reality it's $100 more then what the mattress is actually worth.

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3 years ago

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Say that the economy is in a recession, which is causing the value of gold to fall by three percent. If you have gold reserves w

7nadin3 [17]

Answer:

Step-by-step explanation:

8590 x 0.03 = 257.70

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2 years ago

Simplify the radical expression (5+√3)(5-√3) a. 16 b. 22 c. 25+10√3 d. 16+10√3

Alja [10]

B is the correct answer

$(5 + \sqrt{3} )(5 - \sqrt{3) } \\ = 25 - \sqrt{3 {}^{2} } = 25 - 3 = 22$

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3 years ago

Read 2 more answers

Geometry!!!!!!!!!!!!!!!!!!!!!!!!

Stella [2.4K]

Given:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

Measure of major ∠AOB:

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

$Major \ \angle AOB=360-30$

$Major \ \angle AOB=330^{\circ}$

Thus, the measure of major angle is 330°

Length of the major arc ACB:

The length of the major arc ACB can be determined using the formula,

$m \widehat{ACB}=(\frac{\theta}{360})2 \pi r$

Substituting r = 3 and $\theta=330$ , we get;

$m \widehat{ACB}=(\frac{330}{360})2 \pi (3)$

$m \widehat{ACB}=\frac{1980}{360}\pi$

$m \widehat{ACB}=5.5 \pi$

Thus, the length of the major arc ACB is 5.5π m

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3 years ago