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weeeeeb [17]
3 years ago
6

What is —-8 divided by 2/7—- ?!?

Mathematics
2 answers:
Trava [24]3 years ago
5 0

If it is what I think it is (-8 divided by 2/7), then the answer is -28.


Lilit [14]3 years ago
5 0
-8 ➗ 2/7
First you have to make the -8 a fraction

-8
—
1

Then you multiply it
-8✖️7
1✖️2

Then you’re left with -56/2
Then you do:
-28✖️2
1✖️2

Then you’re left with -28/1

So your answer is -28

Hope this helps! :3
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(5x+6xy-4)-(-6x+7xy+2)
Maslowich

Answer: 11x - xy - 6

Step-by-step explanation:

(5x+6xy-4)-(-6x+7xy+2)

5x + 6xy - 4 + 6x - 7xy -2

11x - xy - 6

3 0
4 years ago
The area of the regular pentagon is 6.9 cm2. What is the perimeter? 2 cm 5 cm 10 cm 20 cm
disa [49]

Given

Area of the regular pentagon is 6.9 cm².

Find out the perimeter of a regular pentagon

To proof

Formula

Area of regular pentagon is

= \frac{1}{4}\sqrt{5(5+2\sqrt{5})}\ a^{2}

As given in the question

area of regular pentagon = 6.9 cm²

now equating the area value with the area formula.

6.9 =\frac{1}{4}\sqrt{5(5+2\sqrt{5})} a^{2}

Now put

√5 = 2.24 ( approx)

put in the above equation

\frac{6.9\times 4}{\sqrt{5(5+2\times2.24)}}=a^{2}\\\frac{27.6}{\sqrt{47.4}}=a^{2}\\\frac{27.6}{6.88}=a^{2}

thus

a² = 4.01

a = √ 4.01

a = 2.0 cm ( approx)

As perimeter  represented the sum of all sides.

i.e regular pentagon have five sides of equal length.

Thus

perimeter of the regular pentagon = 5 × side length

                                                         = 5 ×2.00

therefore the perimeter of the regular pentagon = 10cm

option c is correct

Hence proved









3 0
4 years ago
Read 2 more answers
In division with decimals why do you bring the decimal up
Debora [2.8K]

Answer:

When dividing by decimals, move the decimal point in the dividend the same number of places to the right as you move the decimal point in the divisor.Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
4 ftA wire isneeded tosupport averticalpole 4 feettall. Thecable willbeanchoredto a stake3 feet fromthe baseof thepole. How3 ftA
Oxana [17]

SOLUTION

From the image in the question, we can see that it is a right triangle problem.

And we can use the Pythagoras theorem to solve for the length of cable wire needed.

Pythagoras theorem states that:

\begin{gathered} \text{hypotenuse}^2=opposite^2+adjacent^2 \\ x^2=4^2+3^2 \end{gathered}\begin{gathered} x^2=16+9 \\ x^2=25 \\ \text{Take the square roots of both sides:} \\ \sqrt[]{x^2}=\sqrt[]{25} \\ x=5ft \end{gathered}

Final Answer:

A cable of length 5 feet is needed.

5 0
1 year ago
Will give Brain!! Is it yes
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Answer:

I would say yes

Step-by-step explanation: Hope I helped!

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