If he wants to have the same amount of each item on the wreaths, we need to find the factors of each to find the highest amount of wreaths he can make.
60=2×2×3×5=(2×2×3)×5
36=2×2×3×3=(2×2×3)×3
48=2×2×2×2×3=(2×2×3)×2×2
So, 2×2×3 is in each which is equal to 12 so he can make 12 wreaths with the amount and factor on each wreath below:
If he wants to have the same amount of each item on the wreaths, we need to find the factors of each to find the highest amount of wreaths he can make.
60=2×2×3×5=(2×2×3)×5
36=2×2×3×3=(2×2×3)×3
48=2×2×2×2×3=(2×2×3)×2×2
So, 2×2×3 is in each which is equal to 12 so he can make 12 wreaths with the amount and factor on each wreath below:
The formula is 4/3 times pi times radius cubed. The radius is 9. 4/3 is 1.33. 3.14 times 9 cubed is 81 times 3.14. That is 254.34. 1.33 times 254.34 is 338.2722. That rounds to 338.