Answer: T = 4
Step-by-step explanation:
1. Write all the variables down
P = 8 V = 2X N = 2 R = 2X X = 3
2. Since you know that X = 3 substitute it in to find V and R
V = 2X = 2(3) = 6
R = 2X = 2(3) = 6
3. Find PV
PV = P x V
= 8 x 6
= 48
4. Find NRT
NRT = N x R x T
= 2 x 6 x T
= 12 x T
= 12T
5. Find T
PV = NRT
48 = 12T
12T = 48
divide both sides by 12
T = 48 ÷ 12
T = 4
Answer:
x = 2 or 1/4
Step-by-step explanation:
-13/4 -x= 1/2x -1
Collect like terms
-13/4+1=1/2x+x
Using LCM
(-13+4)/4=(1+2x²)/2x
9/4=(1+2x²)/2x
Cross multiply
9(2x)=4(1+2x²)
18x=4+8x²
Turn into quadratic and solve
8x²-18x+4
Using formulae method
-b±(√b²-4ac)/2a
Where a=8, b= -18 and c=4
(-(-18)±(√(-18)²-4(8)(4))/2(8)
(18±(√324-128))/16
(18±√196)/16
(18±14)/16
(18+14)/16 or (18-14)/16
32/16 or 4/16
2 or 1/4
Replace x with π/2 - x to get the equivalent integral
but the integrand is even, so this is really just
Substitute x = 1/2 arccot(u/2), which transforms the integral to
There are lots of ways to compute this. What I did was to consider the complex contour integral
where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be
which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit
and it follows that
The diameter is 10:
To do this we must use the distance formula:
Distance =√(x2−x1)^2+(y2−y1)^2
So, if we substitute in our values for the origin and endpoint (origin is 1 values, endpoint is 2)
D=✓(-4-0)^2+(-3-0)^2
Simplified, this is
D=✓16+9
D=✓25
D=5
so, the distance from the center of the crcle to the endpoint is 5 (making the radius)
multiply by two, and the diameter of the circle is 10 :)
Answer:
3
Step-by-step explanation:
Each of the lines lengths multiply by 3.
