1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natalija [7]
3 years ago
8

Which parabola will have a minimum value vertex?

Mathematics
2 answers:
hichkok12 [17]3 years ago
8 0

Answer:

The last choice.

Step-by-step explanation:

That would be the last one, with a minimum value of -4.

ollegr [7]3 years ago
8 0

Answer:

IV graph

Step-by-step explanation:

Given is a picture consisting of 4 parabolas with first 3 open up and last one open down.

We are to find the minimum value vertex

Seeing the graph we can write coordinates of vertex as where they turn their direction.

Hence vertices are

Graph           Vertices        y value

I                      (0,5)               5

II                     (0,0)               0

III                    (1,2.5)             2.5

IV                   (0,-4)              -4

Of the 4 y values, IV graph has the minimum value vertex

You might be interested in
Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
3 years ago
A triangle has two sides that measure 4ft and 3ft. Which could be the measure of the third side?
Nezavi [6.7K]
The measure of the third side must be less than the sum of the other two. That property is valid for all triangles.

For this question, call x the measure of the third side. So you must have

x < 4 + 3

x < 7 ft

The only option that satisfies the condition above is

option A) 5 ft.

I hope this helps. =)
7 0
3 years ago
Read 2 more answers
7.
Xelga [282]

Answer:

10x +17y=c (C is the total cost)

6 0
2 years ago
Read 2 more answers
12) A radio transmission tower is 170 feet tall. How long should a guy wire be if it is to be attached 15 feet from the top and
ser-zykov [4K]

The length of guy wire needed to make an angle of 30° with the ground is 310 feet. The angle between the end of the shadow and the vertical side of the building is 23°

<h3>What is trigonometric ratio?</h3>

Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.

a) Let l represent the length of the guy wire.

sin(30) = (170 - 15) / l

l = 310 feet

b) Let Ф represent the angle, hence:

tanФ = 100/230

Ф = 23°

The length of guy wire needed to make an angle of 30° with the ground is 310 feet. The angle between the end of the shadow and the vertical side of the building is 23°

Find out more on trigonometric ratio at: brainly.com/question/24349828

6 0
2 years ago
2(1-4)-3(2+1) equals what
AysviL [449]

It would be -15 as the answer

6 0
3 years ago
Read 2 more answers
Other questions:
  • sam makes $400 per week plus $20 commission oh each new cell phone plan she sells. write an equation to determine how many new p
    6·1 answer
  • 30 POINTS
    6·1 answer
  • Translate the image by (x+4, y - 6)
    8·1 answer
  • Which geometric terms is named by its endpoints
    9·2 answers
  • What are the steps to this equation
    12·2 answers
  • a man 1.30 m tall is on a top of a building. he observed a car on the road at an angle of 60 degrees if the building is 30 m hig
    9·1 answer
  • 1. Slope of line 1: 5/12<br> Slope of line 2: 12/5<br> Parallel<br> Perpendicular<br> Neither
    5·2 answers
  • Algebra help pls ...i uploaded a picture
    14·1 answer
  • A rectangle has a length of 1.5abc and a width of 10abc find the area of the rectangle
    7·1 answer
  • Questions flash
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!