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MAXImum [283]
3 years ago
12

Preform the operation (answer in a+bi form) (i meaning imaginary number).

Mathematics
1 answer:
grin007 [14]3 years ago
7 0
(3+\sqrt9)(2-\sqrt{-25})=\\
(3+3)(2-5i)=\\
6(2-5i)=\\
12-30i
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5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
A rectangle is inscribed in a semicircle of radius 10 as shown in the figure. Find a function that models the area A of the rect
monitta
So based on your question where there is a rectangle inscribed in a semicircle or a radius 10 as shown in your figure. The possible function that could represent the are of the rectangle is A=2x*sqrt(100-x^2) i hope you are satisfied with my answer and feel free to ask for more
5 0
3 years ago
Help please, I'm desperate!
Luden [163]
B. 2.8
Because, 4-1.2=2.8
8 0
3 years ago
Read 2 more answers
Hey i need help! Its due soon
Leto [7]

Answer:

Step-by-step explanation:

2222.88-1690.36=nope

hope this helps!

7 0
3 years ago
Evaluate 9/g+2h+5 when g=3 and h=6
vladimir1956 [14]
To answer this question, simply input the values for g and h:

9/ (3) + 2 (6) + 5 = 9/ 3 + 12 + 5
                           = 9/ 20
          

Hope this helps!
6 0
3 years ago
Read 2 more answers
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