The answer would be -21.6
Cost per meter(C) = $60/m
Length of rectangular field(L) = 50m
L = 2W
-> W = L/2
-> W = 50/2
-> Width of rectangular field = 25m
Cost of one field length(l) = L x C
-> l = 50 x 60
-> l = $3000
Two of the lengths of the field = 2 x l
-> 2 x $3000
-> $6000
Cost of one field width(w) = W x C
-> w = 25 x 60
-> w = $1500
Two of the widths of the field = 2 x w
-> 2 x $1500
-> $3000
Cost of fencing entire field = $6000+$3000
Hence, total field cost = $9000
Answer:
it is B
Step-by-step explanation:
Answer: e= 10
Step-by-step explanation:
Answer:
Answer Below
Step-by-step explanation:
a. 2L+2W≥40
thats equal to 12+2W≥40 since it says the length is 6
That means 2W≥28
That means width ≥ 14
so the width can be 14 or greater
b. Smallest possible width is 14 because the inequality
