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marin [14]
3 years ago
5

What type of endorsement is illustrated by the following example: Tom Ash 7609-25-26-3 A) Restrictive endorsement B) Full endors

ement C) Blank endorsement D) Signature endorsement
Mathematics
1 answer:
Alex Ar [27]3 years ago
6 0

<span>The answer is letter c which is blank endorsement. It is a sign by the maker of an instrument, for instance a check, which allows any holder of the instrument to declare a claim for payment. Since no payee is stated, such an endorsement fundamentally turns the instrument into a bearer security.</span>

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The number p and −1.2 are additive inverses. Drag and drop −1.2 and p to their correct positions on the number line. Drag and dr
klemol [59]

Answer:

p=1.2

Step-by-step explanation:

Additive inverse of any number means a number which can be added to the original number to get

Two numbers are said to be additive inverse of each other if sum of both numbers is 0. For example if 5 is the given number then -5 will be it's additive inverse. So to find additive inverse, we basically change the sign of number.

Given number p is additive inverse off -1.2 so p must be 1.2.

Sum will obviously be 0.

So to graph them on number line, we make a point at -1.2, 1.2 and at 0 for their sum.


3 0
3 years ago
Read 2 more answers
Which of these expressions is equivalent to log9 10? A) log 9 B) log 19 C) 1 log 9 D) 1 log 19
eduard
It’s definitely E. I say this because there is no correct answer.
5 0
3 years ago
Given a population with a mean of muμequals=100100 and a variance of sigma squaredσ2equals=3636​, the central limit theorem appl
lakkis [162]

Answer:

a) \bar X \sim N(100,\frac{6}{\sqrt{25}}=1.2)

\mu_{\bar X}=100 \sigma^2_{\bar X}=1

b) P(\bar X >101)=1-P(\bar X

c) P(\bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".  

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

Let X the random variable that represent the variable of interest on this case, and for this case we know the distribution for X is given by:  

X \sim N(\mu=100,\sigma=6)  

And let \bar X represent the sample mean, by the central limit theorem, the distribution for the sample mean is given by:  

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})  

a. What are the mean and variance of the sampling distribution for the sample​ means?

\bar X \sim N(100,\frac{6}{\sqrt{25}}=1.2)

\mu_{\bar X}=100 \sigma^2_{\bar X}=1.2^2=1.44

b. What is the probability that x overbarxgreater than>101

First we can to find the z score for the value of 101. And in order to do this we need to apply the formula for the z score given by:  

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

If we apply this formula to our probability we got this:  

z=\frac{101-100}{\frac{6}{\sqrt{25}}}=0.833  

And we want to find this probability:

P(\bar X >101)=1-P(\bar X

On this last step we use the complement rule.  

c. What is the probability that x bar 98less than

First we can to find the z score for the value of 98.

z=\frac{98-100}{\frac{6}{\sqrt{25}}}=-1.67  

And we want to find this probability:

P(\bar X

5 0
4 years ago
It took a race car driver 3 hours and 15 minutes to go 500 miles. What was his mean rate of speed, to the nearest tenth of a mil
WINSTONCH [101]
In order to calculate rate or average speed you divide miles by time

I got 153.8 by dividing 500 by 3.25 (the .25 is because 15 minutes is 1/4 of 60) hope this helped!!
4 0
3 years ago
How to write an expression to represent a number g divided by 5
Mrrafil [7]

Answer:

g ÷ 5

Step-by-step explanation:

Variable: g

Operation: Division (represented as ÷)

Constant: 5

Put together the equation:

g ÷ 5

Hope this helps :)

5 0
3 years ago
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