Answer:
graph 1 = greater than 1
graph 2 = 0
graph 3 = 0
graph 4 = less than 0
graph 5 - between 0 & 1
Sorry if anything is wrong!!
<span>(Y-3)^2 = 4y -12 <=> Y^2 - 6Y + 9 = 4y - 12 <=> 4y = Y^2 - 6Y + 21 <=> y = (Y^2 - 6Y + 21)/4. Solving the equation for y means that we have to express y relative to the other quantities in the equation.</span>
Hello :
if cos? is positive and cot? is negative? in 4 <span>quadrant</span>
Answer:
13
Step-by-step explanation:
Not sure, i'm sorry
should be the same logic as
a=b
b=c
a=c
Answer:
Step-by-step explanation:
Adding 1 to both sides of the equation.
Factoring the left side of the equation.
Taking the square root of both sides of the equation.
Subtracting 1 from both sides of the equation.