Help me plzzzzzzzzz!

Pamela called nine repair shops for quotes for auto repairs. The prices are $139, $150, $345, $99, $167, $155, $140, $200, and $

ASHA 777 [7]

Answer:

Step-by-step explanation:

The prices of quoted of auto repairs are as listed below;

$139, $150, $345, $99, $167, $155, $140, $200.

For her to check whether there is an outlier in the data, she needs to find the mean of the set of data. An outlier is a value in a set of a data that varies considerably from other data in a dataset. It may be larger or smaller than other set of datas. An outlier can affect the decision of a set of data to be analysed if nor taken care of.

From the data, the possible outliers are $99 and $345

Mean of the data = sum of all the prices/sample size

xbar = \sum Xi / N

Xi are individual datas

\sum Xi = $139+$150+$345+$99+$167+$155+$140+$200+$160

\sumXi = $1555

Sample size = 9

Mean = $1555/9

Mean = $172.78

Hence the value that would best represent the central tendency is $177.78

5 0

3 years ago

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

3 years ago

How does tap enable transport proteins to move ions across a cell membrane?

Genrish500 [490]

<span>Since charged particles cannot move across the membrane easily due to them being hydrophobic, they require a transport protein that expends energy in the form of ATP. ATP attaches onto the transport protein which changes the shape of the protein allowing ions to flow in, and it leaves a phosphate group turning into ADP.When the molecule has crossed the membrane, the phosphate group is detached from the protein.</span>

6 0

3 years ago

Will give brainliest to person who answers first. Much appreciated

BlackZzzverrR [31]

1. is B.hardware
2. is B. Gpu
3. false I am almost certain there was a version of a pong styled game manipulating roughly the sane code first.
4.false it was not considered a commercial success

4 0

3 years ago

Read 2 more answers

The question is in the jpg.

dexar [7]

First, you need to find the height, in which it says “a height that’s half the length of the longer base side. Can you guess what that is between 7 and 5? It is 7. And you would find half of that which is 3.5. Now you know the height is 3.5. The formula to find a rectangular pyramid's volume is lwh/3 which you would do 7 * 5 * 3.5, which is equal to 122.5, and then you would divide that by 3, which is 40.833 which would round to 40.8, so there is your answer.
It is 40.8 units^3

7 0

3 years ago