Answer:
the total density of the mixture = 3.415 x 10^3 g/mL
Explanation:
given:
density of a substance is 3.4 x 10^3 g/mL
Mixing it with another substance increases the density by 1.5 x 10^1 times.
find:
What is the density of the mixture?
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let density (a) = 3.4 x 10^3 g/mL
density(b) = 1.5 x 10^1 g/mL
since there is no specific density provided for the mixture, we then add both to increase the density,
total density = density(a) + density(b)
total density = 3.4 x 10^3 g/mL + 1.5 x 10^1 g/mL
total density = 3.415 x 10^3 g/mL
therefore,
the total density of the mixture = 3.415 x 10^3 g/mL
Answer:
0.333 mol NH₃
Explanation:
N₂ + 3 H₂ ⇆ 2 NH₃
This is the reaction that produces NH₃. Use the mole ratios to solve. For every 3 moles of H₂ that are consumed, 2 moles of NH₃ are produced.
(0.500 mol H₂) × (2 mol NH₃/3 mol H₂) = 0.333 mol NH₃
You will produce 0.333 moles of NH₃.
<u>Answer:</u> The volume of the container needed is 554.6 L
<u>Explanation:</u>
To calculate the volume of the gas, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 3.0 atm
V = Volume of the gas = ? L
T = Temperature of the gas = ![25^oC=[25+273]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B25%2B273%5DK%3D298K)
R = Gas constant = 
n = number of moles of propane gas = 68.0 moles
Putting values in above equation, we get:
Hence, the volume of the container needed is 554.6 L
Answer:
Concentration of chloride ions = 0.584M
Explanation:
The step by step calculations is shown as attached below.
