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victus00 [196]
3 years ago
6

Why do the names of some ionic compounds include the charge of the metal ion while others do not?

Chemistry
2 answers:
Fantom [35]3 years ago
7 0

Answer:

The correct answer is because there are polyvalent metals.

Explanation:

Most transition metals can form cations with various loads. That is why block d of the periodic table is marked as "variable load". For example, iron is polyvalent, which means "many values", i.e. it can form cations with different loads. For polyvalent metals, we must specify the magnitude of the ion charge. In the case of anions most of the time it is not necessary to specify the magnitude of the charge of the anion.

Have a nice day!

Vitek1552 [10]3 years ago
4 0
The names of some ionic compounds include the charge of the metal ion while others do not because there are ionic compounds that are able to form more than one type of ion especially for metals and these compounds should be distinguished properly to avoid confusion. For instance, the metal cation of iron, we have Fe2+ and Fe3+. Ionic compounds with metal cations have a charge that is invariant from a compound to another does not include the charge of the cation. However, for ionic compounds of a metal with a charge that would vary in different compounds should include the charge of that particular metal cation.
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unit that contains two or more atoms covalently bonded together but that has an overall charge is called a(n) _____ ion. Many __
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Explanation:

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3 years ago
What volume of Co2 (carbon (iv) oxide)
hram777 [196]

Answer:

2.1056L or 2105.6mL

Explanation:

We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:

Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol

Mass of Na2CO3 = 10g

Mole of Na2CO3 =.?

Mole = mass /molar mass

Mole of Na2CO3 = 10/106

Mole of Na2CO3 = 0.094 mole

Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:

Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

From the balanced equation above,

1 mole of Na2CO3 reacted to produce 1 mole of CO2.

Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.

Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:

1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.

Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L

Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL

7 0
4 years ago
Is this correct? This is stoichiometry.
Viefleur [7K]
Yes it’s is bc I said so
7 0
3 years ago
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