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3 years ago

Why do the names of some ionic compounds include the charge of the metal ion while others do not?

Chemistry

2 answers:

Fantom [35]3 years ago

7 0

Answer:

The correct answer is because there are polyvalent metals.

Explanation:

Most transition metals can form cations with various loads. That is why block d of the periodic table is marked as "variable load". For example, iron is polyvalent, which means "many values", i.e. it can form cations with different loads. For polyvalent metals, we must specify the magnitude of the ion charge. In the case of anions most of the time it is not necessary to specify the magnitude of the charge of the anion.

Have a nice day!

Vitek1552 [10]3 years ago

4 0

The names of some ionic compounds include the charge of the metal ion while others do not because there are ionic compounds that are able to form more than one type of ion especially for metals and these compounds should be distinguished properly to avoid confusion. For instance, the metal cation of iron, we have Fe2+ and Fe3+. Ionic compounds with metal cations have a charge that is invariant from a compound to another does not include the charge of the cation. However, for ionic compounds of a metal with a charge that would vary in different compounds should include the charge of that particular metal cation.

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Answer:

1.Solids have definate shape

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3 years ago

A sample of potassium nitrate (49.0 g) is dissolved in 101 g of water at 100 °C, with precautions taken to avoid evaporation of

kvasek [131]

Answer:

Saturated solution

Explanation:

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A amount of the solute, potassium nitrate is dissolved at elevated temperature and on cooling, it precipitates. It means that the solution is saturated at that temperature. <u>Precipitation of the solute at lower temperature indicates that the solution is saturated solution.</u>

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4 years ago

Refer to graph of a chemical reaction. What is true of the reaction shown here?

MAXImum [283]

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3 years ago

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Mariana [72]

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4 years ago

Upon combustion, a compound containing only carbon and hydrogen produces 2.67 g<img src="https://tex.z-dn.net/?f=CO_%7B2%7D" id=

Hoochie [10]

Answer:

$\boxed{\text{CH$_{2}$}}$

Explanation:

1. Calculate the mass of each element

$\text{Mass of C} = \text{2.67 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.7286 g C}\\\\\text{Mass of H} = \text{1.10 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.1231 g H}$

2. Calculate the moles of each element

$\text{Moles of C = 0.7286 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.060 67 mol C}\\\\\text{Moles of H = 0.1231 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.1221 mol H}$

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

$\text{C: } \dfrac{0.06067}{0.06067}= 1\\\\\text{H: } \dfrac{0.1221}{0.06067} = 2.015$

4. Round the ratios to the nearest integer

C:H = 1:2

5. Write the empirical formula

The empirical formula is $\boxed{\text{CH$_{2}$}}$

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3 years ago