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Ainat [17]
3 years ago
13

What is the molar mass, in grams of a mole of an element equal to?

Chemistry
1 answer:
Verizon [17]3 years ago
6 0

Answer:hello

The molar mass in grams of a mole of an element equal to the atomic number of element.

Of course it's not always exactly equal together.

Explanation:

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if it takes 54 ml of 0.100 M naoh to neutralize 125ml of an hcl solution, what is the concentration of the hcl
vichka [17]

Answer:

c = 0.0432moldm ^−3

Explanation:

The first step would be to find the molar ratio in the reaction. Now generally, one can simplify strong acid-strong base reaction by saying:

Acid+Base ->Salt+ Water

4 0
2 years ago
What was the Copernican revolution?
Zolol [24]

The Copernican revolution is about the model of the solar system and was given by a polish astronomer. Option C. The discovery that the universe was expanding.

The Copernican Revolution become the paradigm shift from the Ptolemaic model of the heavens, which described the cosmos as having Earth stationery on the center of the universe, to the heliocentric version with the solar on the center of the solar system.

Copernican Revolution, shift the subject of astronomy from a geocentric understanding of the universe, focused around Earth, to heliocentric knowledge, concentrated across the sun, as articulated by the Polish astronomer Nicolaus Copernicus.

This revolution changed the way of thinking of the solar system. Earlier it was thought that earth is in the center of the solar sysytem,i.e; people believed in the geocentric model, but according to Copernicus the solar system has the sun at the center and the remaining planets revolve around it i.e he believed in a heliocentric model.

Learn more about the Copernican revolution here:-brainly.com/question/11385060

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4 0
2 years ago
Atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron. giv
valina [46]

Answer:

Option A is correct.

Atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron

Explanation:

Atomic orbitals developed using quantum mechanics make use of quantum numbers.

There are four different quantum numbers that all work to give the region of space where a particular electron has the highest probability of being located.

The four quantum numbers that describes an electron's most likely location in an atom include

1) Principal quantum number, denoted by letter n. This quantum number gives the shell that an electron in an atom belongs to. It can take on natural number values from 1 (for the shell closest to the nucleus) through 2, 3, 4.... till rhe outermost shell.

2) Azimuthal/Angular Momentum quantum number, denoted by l. This quantum number describes the subshell or orbital within a shell that the electron belongs to in an atom.

It can take on values that can range from 0 to (n-1). These are the spdf orbitals with s-orbital having l-quantum number of 0, p-orbital with l-quantum number of 1 etc.

3) Magnetic quantum number, denoted by letter m. This describes the sub-orbital that the electron belongs to. It's values for electrons in a particular orbital vary from -l through 0 to +l.

E.g. orbital with l = 1 has electrons whose magnetic quantum number vary from -1, 0, +1.

orbital with l = 2 has electrons whose magnetic quantum number vary from -2, -1, 0, +1, +2.

4) Spin quantum number, denoted by letter s.

This describes the orientation of the electron's spin. Whether clockwise or anti-clockwise in it's sub-orbital. It can take on only values of (+1/2) or (-1/2).

So, these four quantum numbers, numbers that were made known because of quantum mechanics, show that atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron in an atom.

Hope this Helps!!!

5 0
2 years ago
The density of copper is listed as 8.94g/cm​ 3​ . Two students each make three density determinations of samples of the substanc
amm1812

Answer:

Density of the copper = 8.94g/cm^3

Student A results = 7.3gm/cm^3 ,9.4 gm/cm^3 , 8.3gm/cm^3

Student B results = 8.4 gm/cm^3 , 8.8 gm/cm^3 , 8gm/cm^3

From the observations we conclude that

Student A's result is accurate but not  precise as the trials noted are not close to each other.

Student B's result is accurate and precise as the trials noted are close to each other.

Mean density of student A = 7.3 + 9.4 + 8.3 /3 = 8.33gm/cm^3

Mean density of student B = 8.4 + 8.8 + 8 /3 = 8.4 gm/cm^3

both the densities of A and B are 0.5 away from the actual density.

5 0
3 years ago
The area of a triangle with a base of 4 meters and a height of 6 meters.
Tanya [424]

Answer: I believe the answer is 12

Explanation:

8 0
3 years ago
Read 2 more answers
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