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Ainat [17]
3 years ago
13

What is the molar mass, in grams of a mole of an element equal to?

Chemistry
1 answer:
Verizon [17]3 years ago
6 0

Answer:hello

The molar mass in grams of a mole of an element equal to the atomic number of element.

Of course it's not always exactly equal together.

Explanation:

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Can someone help me with #35,37,39,41 please
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4 0
3 years ago
Assume that the pressure inside of the 1 liter balloon is 200,000 Pa, what is the explosive energy in the inside the balloon? Ex
AysviL [449]

Answer:

200 Joules is the explosive energy in the inside the balloon. And that is  9.523\times 10^{-5}1 lb of TNT.

Explanation:

Pressure=\frac{force}{Area}=\frac{Force\times distance}{Area \times distance}=\frac{Energy}{Volume}

Volume of the balloon = V = 1 L = 0.001 m^3

Pressure inside the balloon ,P= 200,000 Pa =200,000 N/m^2

Explosive energy in the inside the balloon be E.

E = Pressure × Volume

E=200,000 N/m^2\times 0.001 m^3=200 Joules

1 lb of TNT = 2.1\times 10^6 J

200 Joules = 200\times \frac{1}{2.1\times 10^6 }1 lb of TNT

= 9.523\times 10^{-5}1 lb of TNT

5 0
3 years ago
Glycerol has a molar mass of 92.09g/mol. Its percent composition is: 39.12% C, 8.75% H,
Sphinxa [80]

Answer:

Molecular formula => C₃H₈O₃

Explanation:

From the question given above, the following data were obtained:

Carbon (C) = 39.12%

Hydrogen (H) = 8.75%

Oxygen (O) = 51.12%

Molar mass of compound = 92.09 g/mol

Molecular formula =?

Next, we shall determine the empirical formula of the compound. This can be obtained as follow:

C = 39.12%

H = 8.75%

O = 51.12%

Divide by their molar mass

C = 39.12 / 12 = 3.26

H = 8.75 / 1 = 8.75

O = 51.12 / 16 = 3.195

Divide by the smallest

C = 3.26 / 3.195 = 1

H = 8.75 / 3.195 = 2.7

O = 3.195 / 3.195 = 1

Thus, the empirical formula is CH₂.₇O

Finally, we shall determine the molecular formula of the compound. This can be obtained as follow:

Empirical formula = CH₂.₇O

Molar mass of compound = 92.09 g/mol

Molecular formula =?

Molecular formula = Empirical formula × n

Molecular formula = [CH₂.₇O]ₙ

92.09 = [12 + (2.7×1) + 16] × n

92.09 = 30.7n

Divide both side by 30.7

n = 92.09 / 30.7

n = 3

Molecular formula = [CH₂.₇O]ₙ

Molecular formula = [CH₂.₇O]₃

Molecular formula = C₃H₈O₃

3 0
3 years ago
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