First, you have to convert mass to moles by making use of molecular weights [N = 14 g/mol and O = 16 g/mol)
A.
5.6/14 = 0.4 mol N
3.2/16 = 0.2 mol O
mol ratio = 2 mol N/1 mol O => N2O
B.
3.5/14 = 0.25 mol N
8.0/16 = 0.5 mol O
mol ratio = 1 mol N/2 mol O => NO2
C.
1.4/14 = 0.1 mol N
4.0/16 = 0.25 mol O
mol ratio = 2 mol N/5 mol O => N2O5
Mg + Cl₂ -----> MgCl₂
24g 1 mol
24g Mg ---- 1 mol Cl₂
Xg Mg ------ 2 mol Cl₂
X = 2×24
<u>X = 48g Mg</u>
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Answer:
1. 0.74mol
2. 0.42mol
3. 2.125mol
4. 0.301mol
5. 4.52 × 10^23 particles
Explanation:
Number of moles (n) in a substance can be found using the formula:
mole (n) = mass/molar mass
Using this formula, the following moles are calculated:
1. Molar of Na = 23g/mol
mole = 17/23
mole = 0.74mol
2. Molar mass of Na2SO4 = 23(2) + 32 + 16(4)
= 46 + 32 + 64
= 142g/mol
Mole = 60/142
mole = 0.42mol
3. Molar mass of CO2 = 12 + 16(2)
= 12 + 32
= 44g/mol
mole = 93.5/44
mole = 2.125mol
4. Molar mass of sodium nitrate (NaNO3) = 23 + 14 + 16(3)
= 23 + 14 + 48
= 85g/mol
mole = 25.6/85
mole = 0.301mol
5. Number of particles in one mole of a substance is 6.022 × 10^23 particles. Hence, in 0.75mol of calcium hydroxide (Ca(OH)2, there will be;
0.75mol × 6.02 × 10^23
= 4.515 × 10^23
= 4.52 × 10^23 particles
Answer:
C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)
2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)
Explanation:
Butane gas (C₄H₁₀) burns in oxygen gas to produce carbon dioxide gas and water vapor. The unbalanced equation is:
C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)
First, we will balance carbon and hydrogen which are in just one compound on each side.
C₄H₁₀(g) + O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)
Finally, we will balance the oxygen atoms.
C₄H₁₀(g) + 6.5 O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)
In order to have integers, we will multiply everý compound by 2.
2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)
