“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
The greatest common factor of the two expressions given as in the task content is; 3v².
<h3>What is the greatest common factor of the two expressions given?</h3>
It follows from the task content that the terms whose greatest common factor are to be determined are: 15v³ and 12 v².
15v³ and 12v²
= 3v²(5v) and 3v²(4)
= 3v²(5v) and (4)
Consequently, in a bid to factorise the two expressions by means of their greatest Common factor, the greatest common factor can be determined as; 3v².
The correct answer choice which therefore represents the greatest common factor as required in the task content is; 3v².
Read more on greatest common factor;
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Gwen is right 3\5 is equivalent to 6\10
if you divide 6\10 by 2 you will get 3\5
The answer is -28/3 or 9.33333333333 have a great day also could I get brainliest
Answer:
Step-by-step explanation:
Given:
Let's distribute the parenthesis
Let's subtract 
from both sides
Let's add to both sides
Now, let's divide both sides by 
to get 
alone
Hope this is helpful
