The resulting equation has a leading degree of 2, hence the system of equation will have 2 solutions
<h3>Quadratic equations</h3>
Quadratic equations are equations that has a leading degree of 2. Given the following system of equations
y=2x
y=x^2+2
Equate to have:
2x = x^2+ 2
Equate to zero
x^2 - 2x +2 = 0
Since the resulting equation has a leading degree of 2, hence the system of equation will have 2 solutions
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Answer:
x>2
Step-by-step explanation:
x+1>3.
Subtract 1 from each side
x+1-1 > 3-1
x>2
There is an open circle at 2 and the lines goes to the right
Answer:
(x ^ 16y ^ 22)
Step-by-step explanation:
For this case we have the following expression:
(x ^ 6y ^ 8) ^ 3 / x ^ 2y ^ 2
Rewriting and for power properties we have:
(x ^ 18y ^ 24) / x ^ 2y ^ 2
(x ^ (18-2) y ^ (24-2))
(x ^ 16y ^ 22)
Answer: this many 4
Step-by-step explanation:
2(2x+7)+2(3x+8y)
=4x+14+6x+16y
=10x+16y+14
Answer:
15.3
Step-by-step explanation:
18-(18×(15%))= 15.3
