Answer:
![\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B5x%2B24%7D%7B36x-6x%5E2%7D%29%5D)
Step-by-step explanation:
Given function:
y =
we know
= ln(A) - ln(B)
thus,
y = 
or
also,
ln(Aⁿ) = n × ln(A)
thus,
y = 
therefore,
![\frac{dy}{dx}=[(\frac{3}{2})\times\frac{1}{(6-x)}\times(0 - 1)] - [ (\frac{2}{3})\times\frac{1}{x}\times1]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5B%28%5Cfrac%7B3%7D%7B2%7D%29%5Ctimes%5Cfrac%7B1%7D%7B%286-x%29%7D%5Ctimes%280%20-%201%29%5D%20-%20%5B%20%28%5Cfrac%7B2%7D%7B3%7D%29%5Ctimes%5Cfrac%7B1%7D%7Bx%7D%5Ctimes1%5D)
or

or
![\frac{dy}{dx}=-[(\frac{3(3x)+2\times2(6-x)}{2(6-x)\times(3x)})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B3%283x%29%2B2%5Ctimes2%286-x%29%7D%7B2%286-x%29%5Ctimes%283x%29%7D%29%5D)
or
![\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B5x%2B24%7D%7B36x-6x%5E2%7D%29%5D)
First, you have to add 16 to both sides because it's the opposite of subtracting.
h-16<24
+16 +16
-16+16 will cancel each other out.
24+16=40
So, h<40
Or in other words, h is smaller than 40.
Hope it helps ^_^
Answer:
Total Distance = 2 miles
Step-by-step explanation:
We know D = RT where
D is distance
R is rate (speed)
T is time
First Leg:
Rate = x mph
Time = 20/60 = 1/3 hour
Hence, D = RT, Distance = x * 1/3 = x/3 miles
Second Leg:
Rate = x - 1
Time = 30/60 = 1/2 hour
Distance = (x - 1) * 1/2 = (x-1)/2
Total distance is the sum of both the legs, hence,
Total distance =
miles
Since both the distance are equal we can equate and solve:

Plugging this x = 3 into the total distance expression, we get:

Total distance, 2 miles
Answer: (3,1)
Explanation: