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4 years ago

Sum of two consercutive integers is -49

Mathematics

1 answer:

lianna [129]4 years ago

8 0

The answer is B. Hard to explain but it is B.

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Darla is 3 times as old as her sister julia.write an algebatic expression for darlas age.let julas age =x

shutvik [7]

D=3x
d= Darla's age
x=Julia's age

3 0

4 years ago

HELP PLEASE 25 POINTS

scoundrel [369]

Answer:

First is < 2nd is = 3rd is <

Step-by-step explanation:

3 0

3 years ago

Which car gets the best gas mileage, or most miles per gallon? A 240 miles on 10 gallons car B 160 miles on 5 gallons car C 30 m

postnew [5]

240 miles : 10 gallons

240/10 miles : 10/10 gallons

24 miles : 1 gallon

Car A travels 24 miles on one gallon of gas.

The mileage is 24 mpg (miles per gallon)

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160 miles : 5 gallons

160/5 miles : 5/5 gallons

32 miles : 1 gallon

The mileage is 32 mpg. So far, car B is better than car A.

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30 miles : 1 gallon

The mileage is 30 mpg, which is not better than car B

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168 miles : 6 gallons

168/6 miles : 6/6 gallons

28 miles : 1 gallon

Mileage is 28 mpg. Car C has better mileage and car B has the best overall.

----------------------------

<h3>Answer: The car with the best mileage is car B with 32 mpg</h3>

The rankings, from best to worst mileage is: B, C, D, A

3 0

3 years ago

Read 2 more answers

What does it mean for a ordered pair to be a solution to a linear equation

jeka57 [31]

Answer:

What's a Solution to a System of Linear Equations? Note: If you have a system of equations that contains two equations with the same two unknown variables, then the solution to that system is the ordered pair that makes both equations true at the same time.

Step-by-step explanation:

8 0

3 years ago

Y=6x4 + 7x2 and x = vw +1

belka [17]

Answer:

w=-1/6 or w=-3

Step-by-step explanation:

Substitute the value of x and y into the first equation and solve for w:

$y=6x^4+7x^2\\10=6(\sqrt{w+1})^4+7(\sqrt{w+1})^2\\10=6(w+1)^2+7(w+1)\\10=6(w^2+2w+1)+7w+7\\10=6w^2+12w+6+7w+7\\0=6w^2+19w+3$

Solve for w with the quadratic formula:

$w=\frac{-b\±\sqrt{b^2-4ac}}{2a} \\w=\frac{-19\±\sqrt{19^2-4(6)(3)} }{2(6)}\\w=\frac{-19\±\sqrt{361-72}}{12} \\w=\frac{-19\±\sqrt{289} }{12} \\w=\frac{-19\±17}{12}$

After simplifying, we get either w=-1/6 or w=-3.

Not sure if w needs to satisfy all conditions while maintaining everything as real numbers, because if w=-3, then x is an imaginary number. But both values work just as fine.

4 0

2 years ago