Answer:
(a) The unit of 70.5 is lbm/ft^3 and the unit of 8.27×10^-7 is in^2/lbf
(b) density = 0.1206g/cm^3
(c) rho = 0.1206exp(8.27×10^-7P)
Step-by-step explanation:
(a) The unit of 70.5 is the same as the unit of rho which is lbm/ft^3. The unit of 8.27×10^-7 is the inverse of the unit of P (lbf/in^2) because exp is found of a constant. Therefore, the unit of 8.27×10^-7 is in^2/lbf
(b) P = 9×10^6N/m^2
rho = 70.5exp(8.27×10^-7× 9×10^6) = 70.5exp7.443 = 70.5×1.71 = 120.6kg/m^3
rho = 120.6kg/m^3 × 1000g/1kg × 1m^3/10^6cm^3 = 0.1206g/cm^3
(c) Formula for rho (g/cm^3) as a function of P (N/m^2) is
rho = 0.1206exp(8.27×10^-7P) (the unit of 0.1206 is g/cm^3)
Answer:
P(y≤4) = 0.629
Step-by-step explanation:
you can see in attachment.
Plug in numbers. if originally, it was V=1/2 * 1 * 1 * 2=1
<span>tripling the dimensions would be V=1/2 * 3 * 3 * 6=27 </span>
<span>it would be 27 times larger. this could also be found by 3^3, just as doubling would render 2^3
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Answer:
a = -3
Step-by-step explanation:
Solve for a:
2 (a + 5) - 1 = 3
Hint: | Distribute 2 over a + 5.
2 (a + 5) = 2 a + 10:
(2 a + 10) - 1 = 3
Hint: | Group like terms in 2 a - 1 + 10.
Grouping like terms, 2 a - 1 + 10 = 2 a + (10 - 1):
(2 a + (10 - 1)) = 3
Hint: | Evaluate 10 - 1.
10 - 1 = 9:
2 a + 9 = 3
Hint: | Isolate terms with a to the left hand side.
Subtract 9 from both sides:
2 a + (9 - 9) = 3 - 9
Hint: | Look for the difference of two identical terms.
9 - 9 = 0:
2 a = 3 - 9
Hint: | Evaluate 3 - 9.
3 - 9 = -6:
2 a = -6
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 2 a = -6 by 2:
(2 a)/2 = (-6)/2
Hint: | Any nonzero number divided by itself is one.
2/2 = 1:
a = (-6)/2
Hint: | Reduce (-6)/2 to lowest terms. Start by finding the GCD of -6 and 2.
The gcd of -6 and 2 is 2, so (-6)/2 = (2 (-3))/(2×1) = 2/2×-3 = -3:
Answer: a = -3
Answer:
The difference between the times is just 6.09
Step-by-step explanation:
Here, we are interested in finding the difference between the times when two athletes finished their races.
While one finished at 24.53, the other finished at 18.44; So the difference between the two will be calculated by subtracting the time which was less from the time which was more;
Mathematically, that would be 24.53 - 18.44 = 6.09
