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Nitella [24]
3 years ago
10

Solve like this pls ————>

Mathematics
1 answer:
Westkost [7]3 years ago
3 0

Answer:

7 - 3 = 4

1 - (-12) = 13

9 + 11 = 20

7 - (-4) = 28

6 × (-3) = -18

(-8) × 9 = -72

5 + (-8) = -40

(-13) -2 = -26

(-13) + (-5) = 65

(-15) × -1 = 16

(-11) -12 = 132

(-9) × 3 = -27

14 + 8 = 22

60 ÷ (-4) = -15

(-4) + (-14) = -18

20 ÷ 5 = 4

(-12) + 8 = -96

6 + 11 = 17

(-14) × 7 = -98

(-12) - 15 = 180

12 × 13 = 156

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The mean number of words per minute (WPM) read by sixth graders is 97 with a standard deviation of 19 WPM. If 75 sixth graders a
andrey2020 [161]

Answer:

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}};

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 97, \sigma = 19, n = 75, s = \frac{19}{\sqrt{75}} = 2.1939

What is the probability that the sample mean would be greater than 101.63 WPM?

This is 1 subtracted by the pvalue of Z when X = 101.63. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{101.63 - 97}{2.1939}

Z = 2.11

Z = 2.11 has a pvalue of 0.9826.

1 - 0.9826 = 0.0174

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

5 0
3 years ago
Match each expression with an equivalent expression.
jolli1 [7]

1=6x-4x

2= 6x-4

3=6-4x

4=6x-4y

6 0
3 years ago
In golf, a score of 0 is called even par. A score of 2 under par is written as -2. A score of 4 over par is written as +4 or 4.
patriot [66]

6 under par is written as -6

2 over par is written as 2

even par is written as 0

even par is written as 0


Total score: add all the numbers together:

-6 + 2 + 0 + 0 = -4  ( 4 under par).

7 0
2 years ago
At the gym, Jasper was able to bench press 224 pounds, which was 7/8 of the weight that Balin was able to bench press. Which sho
Rzqust [24]

Answer:

The answer SHOULD be 7/8=224/x;256 pounds.

You may have made a mistake in inputting it here on Brainly. So look for the one that matches that.

Step-by-step explanation:

This is what we know:

Jasper = 224 pounds

Balin = x

Jasper = 7/8 of x

Now we make an equation for that:

(\dfrac{7}{8})(x) = 224pounds

To match the selections we will isolate 7/8 on one side of the equation:

\dfrac{7}{8}=\dfrac{224}{x}

Using ratio and proportion we can solve for what x is. Multiply 224 by 8 and divide it by 7. Or you can do it this way too:

\dfrac{7}{8}=\dfrac{224}{x}

(7)(x)=(224pounds)(8)

7x=1792pounds

x=\dfrac{1792pounds}{7}=256pounds

So x = 256 pounds

7 0
3 years ago
Read 2 more answers
Assume that the following events are independent:
NNADVOKAT [17]

Answer:

D 0.61

Step-by-step explanation:


0.42

0.69

= 0.6089

7 0
4 years ago
Read 2 more answers
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