Answer:
14 m/s²
Explanation:
Start with Newton's 2nd law: Fnet=ma, with F being force, m being mass, and a being acceleration. The applied forces on the left and right side of the block are equivalent, so they cancel out and are negligible. That way, you only have to worry about the y direction. Don't forget the force that gravity has the object. It appears to me that the object is falling, so there would be an additional force from going down from weight of the object. Weight is gravity (can be rounded to 10) x mass. Substitute 4N+weight in for Fnet and 1kg in for m.
(4N + 10 x 1kg)=(1kg)a
14/1=14, so the acceleration is 14 m/s²
The first choice Always given to you by other people
I hope this helped :3
Answer: The new force is:
F1 = -(9/16)*F0
where F0 is the initial force.
Explanation:
The charges of the spheres is q1 = 8Q and q2 = -2Q
and as you know, the force between charged objects is:
F = k*q1*q2/r^2
where k is a constant and r is the distance
F0 = -(k16Q^2)/r^2
where the negative sign means that the force is attractive.
Now, when the spheres touch each other, the charge must be distributed equally in both spheres. So the total charge is q1 + q2 = 8Q - 2Q = 6Q
then each sphere has now a charge of 3Q.
The new force is:
F1 = k*3Q*3Q/r^2 = (k*9*Q^2)/r^2 = -(9/16)*F0
You can see that F1 is positive, this means that the force now is repulsive.
Explanation:
Impulse is the change in momentum. It is also equal to the average force times the change in time.
J = Δp
F Δt = m Δv
The change in momentum is a fixed number; your mass, initial velocity, and final velocity are constant.
F Δt = k
So force and time are inversely proportional. What this means is, we can either have a large force over a short period of time, or a small force over a long period of time.
Obviously, we want a small force over a long period of time. Without airbags, your head would hit the steering wheel very quickly. With airbags, your head has time to decelerate, so there's less force.
Let the stone is dropped off a cliff of height S m ft.
Given, initial velocity of the stone, u= 0 ft/s
Final velocity of the stone, v= 104 ft/s
Acceleration of the stone= Acceleration due to gravity = 32 ft/s²
Using the third equation of motion,
v² - u² = 2aS
Substituting the values we get,
S= 169 ft
Height of the cliff is 169 ft.
