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iogann1982 [59]
4 years ago
11

The intensity of sunlight incident on the surface of a solar panel on your roof is 1000 W/m^2. Calculate the sunlight energy abs

orbed by the panel in one hour if the length of the panel is 6.00 m and its width is 4.00 m and the sunlight is incident perpendicularly on the panel.
Physics
1 answer:
melisa1 [442]4 years ago
5 0

Answer:

8.64 x 10^7 J

Explanation:

Intensity of sunlight, I = 1000 W/m^2

Length of panel, L = 6 m

Width of panel, W = 4 m

Area of the panel, A = L x W = 6 x 4 = 24 m^2

time, t = 1 hour = 3600 second

Energy = Intensity x area of panel x time

E = 1000 x 24 x 3600 = 8.64 x 10^7 J

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Which has the most kinetic energy?
lara31 [8.8K]

Answer:

I think A golf ball shot out of a small cannon

Explanation:

3 0
2 years ago
A coin released at rest from the top of a tower hits the ground after falling 1.5 s. What is the speed of the coin as it hits th
Inessa05 [86]

initially coin is at rest and then it drop for total time t = 1.5 s

so here the speed of the coin at which it will hit the floor is to be find

v_f = v_i + at

here we know that

v_i = 0

a = 9.8 m/s^2

t = 1.5 s

now from above equation

v_f = 0 + 1.5 (9.8)

v_f = 14.7 m/s

so it will hit the floor with speed 14.7 m/s

3 0
3 years ago
A 20 kg crate initially at rest on a horizontal floor requires a 80 N horizontal force to set it in motion. Find the coefficient
e-lub [12.9K]

Answer:

<em>The coefficient of static friction between the crate and the floor is 0.41</em>

Explanation:

<u>Friction Force</u>

When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration and velocity because the friction force opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

Fr=\mu N          [1]

Where \mu is the coefficient of static or kinetics friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W = m.g

The crate of m=20 Kg has a weight of:

W = 20*9.8

W = 196 N

The normal force is also N=196 N

We can find the coefficient of static friction by solving [1] for \mu:

\displaystyle \mu=\frac{Fr}{N}

The friction force is equal to the minimum force required to start moving the object on the floor, thus Fr=80 N and:

\displaystyle \mu=\frac{80}{196}

\mu=0.41

The coefficient of static friction between the crate and the floor is 0.41

7 0
3 years ago
What’s the power if a student does 2240j of work for 2.8 seconds
Alex787 [66]

Answer:

800 Watts

Explanation:

Power = Work/time

Working in SI units, Power = Watts, Work = Joules, Time = seconds.

Power = 2240J/2.8s = 800 Watts.

7 0
3 years ago
Which statement best describes the importance of joints in the roadways of Bridges ?
Sergeeva-Olga [200]

Answer:

c. Joints allow the roadway to expand and contract as cars put force on the bridge

Explanation:

The reasons why joints are allowed on roadway is to accommodate the contraction and expansion of the road as cars put force on them.

  • Most materials used in making roadways are susceptible to expansion and contraction.
  • When a measure of force is applied their length either increases or decreases depending on the type of force.
  • To accommodate these changes, joints are placed in roadways
3 0
3 years ago
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