The answer should be d because they are constantly rotating
Answer:
Explanation:
Suppose when bucket is half full it has a mass of 2 m rotating in a circle of radius r
When Bucket is quarter full then it has a mass of m rotating in a circle of radius r.
When an object moves in a circular path then it experiences an inward force which is given by

where v=velocity of bucket
Force in case 2 is given by

Thus
therefore force required in half bucket is more than force required in quarter bucket full.
A volt-ampere is the product of the voltage and the current (measured in amperes) of the electricity on a line. Voltage is electric potential difference in charge between two points in an electrical field. it is measured in volts. while the Current is the flow of electrical charge which is often carried by moving electrons in a wire or a conductor. Current is measured in Amperes.
The previous part of the exercise says:
"<span>Engineers are designing a system by which a falling mass m imparts kinetic energy to a rotating uniform drum to which it is attached by thin, very light wire wrapped around the rim of the drum. There is no appreciable friction in the axle of the drum, and everything starts from rest. This system is being tested on Earth, but it is to be used on Mars, where the acceleration due to gravity is 3.71 m/s². In the Earth tests, when m is set to 18.0 kg and allowed to fall through 5.50 m, it gives 300.0 J of kinetic energy to the drum."
Since Kearth = Kmars, we have, for conservation of energy, that also the potential energies must be equal:
Uearth = Umars
which means:
m </span>· gearth · hearth = m · gmars <span>· hmars
we can solve for hmars:
hmars = (gearth / gmars) </span>· hearth
= (9.8 / 3.71) · 5.50
= 14.53m
Therefore, the correct answer will be: the mass would have to fall from an height of 14.53m.
Answer:
a) I = 2279.5 N s
, b) F = 3.80 10⁵ N, c) I = 3125.5 N s and d) F = 5.21 10⁵ N
Explanation:
The impulse is equal to the variation in the amount of movement.
I =∫ F dt = Δp
I = m
- m v₀
Let's calculate the final speed using kinematics, as the cable breaks the initial speed is zero
² = V₀² - 2g y
² = 0 - 2 9.8 30.0
= √588
= 24.25 m/s
a) We calculate the impulse
I = 94 24.25 - 0
I = 2279.5 N s
b) Let's join the other expression of the impulse to calculate the average force
I = F t
F = I / t
F = 2279.5 / 6 10⁻³
F = 3.80 10⁵ N
just before the crash the passenger jumps up with v = 8 m / s, let's take the moments of interest just when the elevator arrives with a speed of 24.25m/s down and as an end point the jump up to vf = 8 m / n
c) I = m
- m v₀
I = 94 8 - 94 (-24.25)
I = 3125.5 N s
d) F = I / t
F = 3125.5 / 6 10⁻³
F = 5.21 10⁵ N