The intensity of sunlight incident on the surface of a solar panel on your roof is 1000 W/m^2. Calculate the sunlight energy abs
orbed by the panel in one hour if the length of the panel is 6.00 m and its width is 4.00 m and the sunlight is incident perpendicularly on the panel.
1 answer:
Answer:
8.64 x 10^7 J
Explanation:
Intensity of sunlight, I = 1000 W/m^2
Length of panel, L = 6 m
Width of panel, W = 4 m
Area of the panel, A = L x W = 6 x 4 = 24 m^2
time, t = 1 hour = 3600 second
Energy = Intensity x area of panel x time
E = 1000 x 24 x 3600 = 8.64 x 10^7 J
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