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loris [4]
3 years ago
15

What is another way to write the expression t×(14-5)

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0
T(14 - 5) = 14t - 5t or t(14) - t(5) 
ryzh [129]3 years ago
3 0
Well T times fourteen minus five = eleven
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Help answer and EXPLAIN STEP BY STEP
pychu [463]

15. (-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)

Step 1: Distribute the subtraction sign to all the numbers in the second set of parentheses...

(-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)

-k^{3} -5k^{2} +1 - 6k^{3} +k^{2} +2

Step 2: Combine like terms (k^{2}'s go with k^{2}'s)

-k^{3} -5k^{2} + 1 - 6k^{3}+k^{2} +2

-5k^{2} +k^{2}

-4k^{2}

-k^{3} -4k^{2} + 1 - 6k^{3}+2

Step 3: Combine like terms (k^{3}'s go with k^{3}'s)

-k^{3} -4k^{2} + 1 - 6k^{3}+2

-k^{3} + (- 6k^{3})

-7k^{3}

-7k^{3} -4k^{2} + 1 +2

Step 4: Combine like terms (normal numbers go with normal numbers)

-7k^{3} -4k^{2} + 1 +2

1 + 2

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-7k^{3} -4k^{2} + 3

You were correct!

16. 49m^2 - 84mn + 36n^2

I don't really know how to explain this one but I got: (7m-6n)(7m-6n)

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3 years ago
Solve for the inequality? <br> A OR B?
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3 years ago
An article gave the accompanying data on ultimate load (kN) for two different types of beams. Assuming the underlying distributi
krok68 [10]

Answer:

The 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams is (-11.937, -6.863).

Step-by-step explanation:

We have to calculate a 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams.

The sample 1 (Fiberglass), of size n1=26 has a mean of 33.4 and a standard deviation of 2.2.

The sample 2 (Carbon), of size n2=26 has a mean of 42.8 and a standard deviation of 4.3.

The difference between sample means is Md=-9.4.

M_d=M_1-M_2=33.4-42.8=-9.4

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{2.2^2}{26}+\dfrac{4.3^2}{26}}\\\\\\s_{M_d}=\sqrt{0.186+0.711}=\sqrt{0.897}=0.9473

The critical t-value for a 99% confidence interval is t=2.678.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_{M_d}=2.678 \cdot 0.9473=2.537

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = -9.4-2.537=-11.937\\\\UL=M_d+t \cdot s_{M_d} = -9.4+2.537=-6.863

The 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams is (-11.937, -6.863).

8 0
3 years ago
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