Se hizo un estudio entre los estudiantes de Licenciatura en ingeniería de software y sistemas computacionales, a 40 de estos est
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Answer:
<em>5</em><em> players participated in the tournament.</em>
Step-by-step explanation:
In a small chess tournament, 20 matches were played.
Let us assume that n number of players participated in the tournament
As in each game 2 players play, so the number of ways they can play is,
As they played 2 games with every other participant in the tournament.
So the total number of games is,
But it is given to be 20, so
As , so we get n=5.
Therefore, 5 players participated in the tournament.
Answer:
40.1% probability that he will miss at least one of them
Step-by-step explanation:
For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
0.95 probaiblity of hitting a target
This means that
10 targets
This means that
What is the probability that he will miss at least one of them?
Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So
We want P(X < 10). So
In which
40.1% probability that he will miss at least one of them