For this graph, mark the statements that are true.

Mathematics

2 answers:

statuscvo [17]3 years ago

6 0

Answer:

The domain is the set of all real numbers and the range is the set of all real numbers greater than or equal to zero

Step-by-step explanation:

satela [25.4K]3 years ago

3 0

The answer might be D sir

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Dolbear's law states the relationship between the rate at which Snowy Tree Crickets chirp and the air temperature of their envir

Shtirlitz [24]

For this case, the first thing we are going to do is rewrite the equation correctly.
We have then:
T = 50 + (N-40) / 4
We substitute the value of N = 98, we have then:
T = 50 + (98-40) / 4
T = 64.5 degrees Fahrenheit.
Answer:
the temperature in degrees Fahrenheit, T is:
T = 64.5 degrees Fahrenheit.

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3 years ago

Which term is a term in this expression?<br> -3x-7(x+4)

sdas [7]

Answer:

x + 4

Step-by-step explanation:

3 0

3 years ago

I need help is it a b c or d

Lunna [17]

The answer is d)3 because each number gets multiplied by 3 to qual the next number

7 0

3 years ago

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If Nancy needs 3/1/4 cups of oatmeal,how many 1/4 cups of oatmeal will she use

PIT_PIT [208]

The answer is 12 1/4. how I got my answer.

Their are 4 quarters to a whole, so that means all I have to do is multiply 4×3=12, then add 1/4+12= 12 1/4.

I hope this helps!

8 0

3 years ago

Question regarding logarithms.

Eddi Din [679]

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

$\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}$

$\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}$

6 0

3 years ago

Read 2 more answers