A transform fault boundary is the correct answer.
PART a)
Momentum is defined as product of mass and velocity
so here initial momentum is
given that
m = 0.3 kg
v = 18 m/s
towards East
Part b)
Since puck was initially at rest so here initial momentum must be ZERO
so here to find the force we can use
so here we have
time interval = 0.25 s
now from above equation
Part c)
Due to friction the puck lose its speed by 5 m/s
final speed = 18 - 5 = 13 m/s
mass = 0.3 kg
final momentum = (0.3)(13) = 3.9 kg m/s
now the impulse due to friction force is given as
Part d)
initial momentum of block will be ZERO as it is placed at rest
Initial momentum of the puck is given as
so total momentum before collision is given as
Part e)
since the system is isolated and there is no external force on it
So here momentum will remain conserved
so here we have
so final combined speed will be 2.6 m/s
Answer:
Solution:
As per the question:
Area of the plates is given by 'A'
Separation distance between the plates is 'd'
Now, after insertion of the metal plate with same area 'A' and thickness, a < d
in between the plates, the capacitance of the capacitor changes.
The capacitance of the air capacitor (parallel plate) is generally given by:
where
C = Capacitor's capacitance
= Permittivity of the free space
Now, when the metal slab is inserted the distance is reduced to (d - a)
Thus
Explanation:
V = 3 cm/s = 0.03 m/s. BY THE FORmULA OF K.E. K.E = 1/2 mV^2. 300 =1/2 m (0.03)^2. m = 300 x 2/0.0009.