The correct answer is letter C. Volume is decreasing. For a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume<span> are </span>inversely proportional<span>. </span>
Mass=density*volume
1*40=40g/0.04kg
Answer:
15 KJ
Explanation:
The quantity of heat (Q) required is given as:
Q = mcΔθ + mL
where m is the mass of ice, c is its specific heat capacity, L is its specific latent heat andΔθ is the change in temperature.
Given: m = 20g, temperature of ice = 0
, specific heat capacity of water = 4200 J/kg
, latent heat of fusion of ice = 3.3 x 10^(5) J/kg, temperature of water = 100
.
Q = m (cΔθ + L)
= 0.02(4200 x (100) + 330000)
= 0.02(420000 + 330000)
= 0.02 (750000)
Q = 15000
Q = 15000 Joules
Q = 15KJ
The quantity of heat needed to complete the conversion is 15 KJ.
To solve this problem we will apply the concepts related to voltage as a dependent expression of the distance of the bodies, the Coulomb constant and the load of the bodies. In turn, we will apply the concepts related to energy conservation for which we can find the speed of this

Here,
k = Coulomb's constant
q = Charge
r = Distance to the center point between the charge
From each object the potential will be

Replacing the values we have that


Now the potential two is when there is a difference at the distance of 0.1 from the second charge and the first charge is 0.1 from the other charge, then,


Applying the energy conservation equations we will have that the kinetic energy is equal to the electric energy, that is to say

Here
m = mass
v = Velocity
q = Charge
V = Voltage
Rearranging to find the velocity

Replacing,


Therefore the speed final velocity of the electron when it is 10.0 cm from charge 1 is 
The radius of each jawbreaker is approximately 0.68 cm.
<h3>Volume of a sphere;</h3>
where
r = radius
Therefore,
23 g = 32.3 cm³
0.94 g = ?
cross multiply
volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³
Therefore,
volume of each jawbreaker = 4 /3 πr³
1.32 = 4 / 3 × 3.14 × r³
r³ = 1.32 /4.18666666667
r³ = 0.31533683707
r = ∛0.31533683707
r = 0.680651651 = 0.68
Therefore, the radius of each jawbreaker is approximately 0.68 cm.
learn more on radius here: brainly.com/question/19172427