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NemiM [27]
3 years ago
12

Which of the following would not count toward a weighted GPA?

Computers and Technology
2 answers:
marta [7]3 years ago
7 0
D AP music theory is the answer
dybincka [34]3 years ago
4 0

A) High School Biology

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What is the statement describing? Agile team continuously adapt to new circumstances and enhance the methods of value delivery
Vera_Pavlovna [14]

Answer:

Continuous Integration

Explanation:

In continuous integration process, A program or piece of code is edited, tested and validated by team of software developers or contributors to complete and deploy the single project. This practice will improve the quality and reliability of the code.

Improvement, delivery and deployment are the three different phases, to complete the process of continuous integration.The individuals who contribute in a code or program  in terms of improvement, delivery and deployment make a team that leads to continuous integration.

So, Agile team Continuously adapt Continuous Integration to new circumstances and enhance the methods of value delivery.

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3 years ago
Type of media that uses laser technology to store data and programs is
olganol [36]
The answer is compact disc or cd, only device that use lasers (that arent proprietary floppys) 
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Consider an array inarr containing atleast two non-zero unique positive integers. Identify and print, outnum, the number of uniq
Delvig [45]

Answer:

Program.java  

import java.util.Scanner;  

public class Program {  

   public static boolean isPalindrome(String str){

       int start = 0, end = str.length()-1;

       while (start < end){

           if(str.charAt(start) != str.charAt(end)){

               return false;

           }

           start++;

           end--;

       }

       return true;

   }  

   public static int countPalindromePairs(String[] inarr){

       int count = 0;

       for(int i=0; i<inarr.length; i++){

           for(int j=i+1; j<inarr.length; j++){

               StringBuilder sb = new StringBuilder();

               sb.append(inarr[i]).append(inarr[j]);

               if(isPalindrome(sb.toString())){

                   count++;

               }

           }

       }

       return count == 0 ? -1 : count;

   }

   public static void main(String[] args) {

       Scanner sc = new Scanner(System.in);

       String line = sc.next();

       String[] inarr = line.split(",");

       int count = countPalindromePairs(inarr);

       System.out.println("RESULT: "+count);

   }

}

Explanation:

OUTPUT:

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