Question

Line m includes the points (-3, 3) and (-4,-6). Line n has the same slope as line m and

Answer 1

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

The slope of a line is given by:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

We have that the line m passes through the following points:

$(x_ {1}, y_ {1}): (-3,3)\\(x_ {2}, y_ {2}): (-4, -6)$

So, the slope of the line m is:

$m = \frac {-6-3} {- 4 - (- 3)} = \frac {-9} {- 4 + 3} = \frac {-9} {- 1} = 9$

Line n has the same slope so the equation is of the form:

$y = 9x + b$

We have as data that the y-intercept is $-\frac{2} {3}$. Thus, we have that the equation of line n is:

$y = 9x- \frac {2} {3}$

ANswer:

$y = 9x-\frac {2} {3}$