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3 years ago

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A boy wins a carnial games 50% of the time. He uses a spinnser with equal-sized sections labeled 0 - 9 to simulate trials of the

game. In the simulation, the numbers 0-4 represent winnning. Numbers 5-9, represent losing. Based on the simulations below that represent the boy playing the game 3 times, what is the probability he will win all 3 times? HINT: Your answer must be written in fraction: Favorable Outcome/Total Possible Outcome.
412 750 236 808 904 237 424 648 121 208

2 answers:

Alenkasestr [34]3 years ago

8 0

Answer:

412,424,121

Step-by-step explanation:

3/10 equals 309.

Nina [5.8K]3 years ago

5 0

Answer:

is it one of the numbers down below it? Cuase if it is then probablay 648

Step-by-step explanation:

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find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0

Citrus2011 [14]

Answer:

Radius: $r =\frac{\sqrt {21}}{6}$

$Center = (-\frac{3}{2}, -\frac{2}{3})$

Step-by-step explanation:

Given

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Solving (a): The radius of the circle

First, we express the equation as:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

So, we have:

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Divide through by 9

$x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0$

Rewrite as:

$x^2 + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}$

Group the expression into 2

$[x^2 + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}$

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

Next, we complete the square on each group.

For $[x^2 + 3x]$

1: Divide the $coefficient\ of\ x\ by\ 2$

2: Take the $square\ of\ the\ division$

3: Add this $square\ to\ both\ sides\ of\ the\ equation.$

So, we have:

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

$[x^2 + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Factorize

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Apply the same to y

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}$

Add the fractions

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}$

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

By comparison:

$r^2 =\frac{7}{12}$

Take square roots of both sides

$r =\sqrt{\frac{7}{12}}$

Split

$r =\frac{\sqrt 7}{\sqrt 12}$

Rationalize

$r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}$

$r =\frac{\sqrt {84}}{12}$

$r =\frac{\sqrt {4*21}}{12}$

$r =\frac{2\sqrt {21}}{12}$

$r =\frac{\sqrt {21}}{6}$

Solving (b): The center

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

From:

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

$-h = \frac{3}{2}$ and $-k = \frac{2}{3}$

Solve for h and k

$h = -\frac{3}{2}$ and $k = -\frac{2}{3}$

Hence, the center is:

$Center = (-\frac{3}{2}, -\frac{2}{3})$

6 0

2 years ago

Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of succes

lys-0071 [83]

Answer:

Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

We are given a binomial distribution with 680 trials and a probability of success of 0.55.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 680 trials

r = number of success

p = probability of success which in our question is 0.55

So, it means X <em>~ </em> $Binom(n=680, p=0.55)$

<em><u>Now, we have to find the mean and standard deviation of the given binomial distribution.</u></em>

Mean of Binomial Distribution is given by;

E(X) = n $\times$ p

So, E(X) = 680 $\times$ 0.55 = 374

Standard deviation of Binomial Distribution is given by;

S.D.(X) = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{680 \times 0.55 \times (1-0.55)}$

= $\sqrt{680 \times 0.55 \times 0.45}$ = 12.97

Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.

3 0

3 years ago

calvin paints pictures and sells them at art shows. He charges $56.25 for a large painting. He charges $25.80 for a small painti

stellarik [79]

The answer is 1,111.90

3 0

3 years ago

Read 2 more answers

Combine like radicals to get your answer. <br><br> image attached

spin [16.1K]

Answer:

So the final answer is

$-8\sqrt{3}$

Step-by-step explanation:

Radicals:

In mathematics, a radical expression is defined as any expression containing a radical (√) symbol. Many people mistakenly call this a 'square root' symbol, and many times it is used to determine the square root of a number. However, it can also be used to describe a cube root, a fourth root, or higher.

The given expression is

$-5\sqrt{3} -3\sqrt{3}$

Now take common radical out so we will get

$\sqrt{3}(-5-3)$

Now add the Parenthesis part.

$\sqrt{3}(-8)$

So the final answer is

$-8\sqrt{3}$

5 0

3 years ago

I NEED HELP! PLEASE! I WILL GIVE OUT BRAINLIST IF CORRECT!

Lisa [10]

Answer:

A reflection on the y axis, then a reflection on the x axis, then a translation of 7 units to the left

Step-by-step explanation:

plz mark me as brainliest

8 0

2 years ago