Question

Use the quadratic formula to determine the solutions to the quadratic equation. Write your answers as decimals, and round to the nearest hundredth (2 decimal spots).
6x2+4x−3=0

Answer 1

Answer:

Either   x≈ -1.12    or  x ≈0.45      

Step-by-step explanation:

Using the quadratic formula to solve this, we will follow the steps below;

First, write  down the quadratic formula;

x = -b ±√b² - 4ac /2a

From the question, the equation given is:   6x²+4x−3=0

comparing the equation given withe standard equation  ax² + bx + c=0

a= 6      b= 4    and c = -3

We can now proceed to insert the values into the formula;

x = -4 ±√4² - 4(6)(-3) /2(6)

x = -4 ±√16+72    /12  

x = -4 ±√88    /12

Either x = -4+√88 /12

           x ≈0.45    

OR  

x = -4 -√88   /12

x≈ -1.12

Either   x≈ -1.12    or  x ≈0.45      

 

Answer 2

Answer:

x1 = 0.45 and x2 = -1.12

Step-by-step explanation:

To solve the equation 6x2+4x−3=0 using the quadratic formula, we use the following equation:

x = [-b ± √(b2 - 4ac)] / 2a

Where a, b and c are coefficients of the quadratic equantion (in our case, a = 6, b = 4 and c = -3)

So we have that:

x1 = [-4 + √(16 + 72)] / 12 = (-4 + 9.3808) / 12 = 0.4484

x2 = [-4 - √(16 + 72)] / 12 = (-4 - 9.3808) / 12 = -1.1151

Rounding to nearest hundredth, we have x1 = 0.45 and x2 = -1.12