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earnstyle [38]
3 years ago
13

A doctor ordered 300 ml of a 10% solution,but the pharmacy only has 5% and 25% solutions. How many millimeters of each solution

should the pharmacist mix to get the prescribed medication for the man?
Mathematics
1 answer:
serg [7]3 years ago
3 0

Answer:


Step-by-step explanation:

(300 * 0.1) = (0.05 * x) + (0.25 * (300 - x))

30 = 0.05x + 75 - 0.25x

-45 = -0.2x

x = 225.

So there would be...

<h2>225 milliliters of 5% solutions</h2><h2>and</h2><h2>75 milliliters of 25% solutions.</h2><h2 /><h2>Feel free to contact me if you have issues or difficulties.</h2>
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A circle has an arc of length 20π that is intercepted by a central angle of 180°. What is the radius of the circle?
Bond [772]

Answer:

10π

Step-by-step explanation:

RULE:  The angle measure of the central angle is congruent to the measure of the intercepted arc.  

RULE:  Central Angle = Arc length

Given:  

Arc length (20 π) = central angle (180)

we know 180 degrees is a straight line, thus a semi-circle is created.  This would be the diameter.  

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10π

8 0
3 years ago
PLEASE HELP TEST DUE IN 10 MINUTES WILL GIVE BRAINLIEST AND GOOD REVIW!
Eva8 [605]

Answer:

y=3/2(x)+4

Step-by-step explanation:

Because line AB is perpendicular to line BC, the slope of AB is equal to 3/2. Substituting (-2,1) into the new equation gives us "1=3/2(-2)+b" which simplifies to 1=-3+b. This means that b=4.

6 0
3 years ago
Please help! A chemist has 100ml of 25% acid solution. How much of the solution does she need to drain and replace with 70% acid
ratelena [41]

Answer:

77.78

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP I NEED THIS ASAP ! 100 POINTS!!
Finger [1]

Answer:

Part A: The population are the American adult citizens, excluding the ones from Alaska and Hawaii. The population is the people which the sample is trying to represent, as a hole.

The sample is a portion of this population, and in this case is represented by a randomly selected amount of people whose response to the interview has been selected.

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Step-by-step explanation:

6 0
2 years ago
If lim x-&gt; infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b
MAXImum [283]

We have

\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}

So

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0

The rational term vanishes as <em>x</em> gets arbitrarily large, so we can ignore that term, leaving us with

\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0

and this happens if <em>a</em> = 1 and <em>b</em> = -1.

To confirm, we have

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as required.

3 0
3 years ago
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