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yawa3891 [41]
3 years ago
9

Given: ABCD is a rectangle, AC ∩BD = O, m∠ABD=30°, AC=16 in. Find BC.

Mathematics
1 answer:
nata0808 [166]3 years ago
7 0

Answer:

8

Step-by-step explanation:

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Brut [27]
B, D and F are midpoints
so
DB = 1/2 (AE)
BF = 1/2 (CE)
DF = 1/2(AC)
in this case you only need to find out DF = ?
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DF = 1/2 (AC)
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What would be the measure of arc DF, DEB, and BEC?? Thanks!!
olga2289 [7]

Answer:

Part A) The measure of arc DF is 129°

Part B) The measure of arc DEB is 270°

Part C) The measure of arc BEC is 321°

Step-by-step explanation:

Part A) What would be the measure of arc DF?

we know that

CF is a diameter

so

The measure of arc CDEF is equal to 180 degrees

arc CD+arc DE+arc EF=180°

substitute the given values

51°+90°+arc EF=180°

arc EF=180°-(51°+90°)=39°

arc DF=arc DE+arc EF

arc DF=90°+39°=129°

Part B) What would be the measure of arc DEB?

we know that

arc DEB=arc DE+arc EFB

we have

arc DE=90°

arc EFB=180° -----> because EB is a diameter

substitute

arc DEB=90°+180°=270° -----> 3/4 of a circle

Part C) What would be the measure of arc BEC?

we know that

arc BEC=arc DEB+arc CD

we have

arc DEB=270°

arc CD=51°

substitute

arc BEC=270°+51°=321°

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Andrews [41]

The answer for the following question is option A.

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3 years ago
Read 2 more answers
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