This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
Prime factorization of 2·5·2=2^2·5
The answer for this is less than 887
We find the length of AD using the similarity of right triangle property. See image attached.
AD² = BD × CD
AD² = 9 × 36
AD² = 324
AD² = 18²
AD = 18
The length of AD is 18 units
Answer:
7 km
Step-by-step explanation:
Substitute:
The equation for area of a semi-circle is 
A = 
76.97 = 
Multiply by 2 on both sides:
2(76.97) = (
)2
153.94 = 
Divide by pi on both sides:
153.94 = 
/pi /pi
49.03 ≈ 
Find the square root:

7 = r