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sashaice [31]
3 years ago
15

write an expression that has a value of 100 and follows these restrictions. (1) uses each of the four operations at most once. (

2) uses no parentheses. (3) uses only the digit 3.
Mathematics
2 answers:
Artyom0805 [142]3 years ago
8 0

Answer:

1) uses each of the four operation at most once:

("at most" basically means either we have to use any 1 operation at a time or no operation must be used)

if 100 is to be written without any operation then 100=100.

if only addition is used then 100=51+49

if only subtraction is used then 100=121-21

if only multiplication is used then 100=50×2

if only division is used then 100=\dfrac{500}{5}.

2) if we don't have to use any parentheses

then 100=55+45 or 100 could be expressed other ways as well.

3) uses only digit 3:

100=33\times 3+\dfrac{3}{3}.







posledela3 years ago
5 0
33 * 3 + 3/3 = 100

I do not believe u have to use all of the operations because it says " at most once ". 
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den301095 [7]

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-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

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Using this property , we have ,

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This can be written as ,

\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}

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\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}

Subtracting the numbers inside the brackets ,

\rm\implies (-1)^{2n - 1 }

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

\rm\implies\boxed{\quad \red{ -1 }\quad }

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Answer:

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3 0
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