Answer:
SORRY I don't know second number . I did only first .
Answer:
Step-by-step explanation:
area of base = π4² = 16π in²
lateral area = 2πrh = 2π·4·6 = 48π in²
surface area = 2×16π + 48π = 80π in² ≅ 251.3 in²
Answer:
Option B. 5.5 ft²
Step-by-step explanation:
Perimeter of the square piece of land = length of fence required
4(length of a side of the square) = 24 ft
Length of a side = 6 ft
Area of the square land = (Side)²
= 6²
= 36 square ft
Area of the side walk = Area of the square - [Area of two triangles separated by the sidewalk]
= 36 - [1/2 (Area Of The Sqaure) + 1/2 (Base) (Height) ]
= 36 - [36/2 + 1/2 (6 - 1) (6 - 1)]
= 36 - (18 + 12.5)
= 36 - 30.5
= 5.5 ft²
Therefore, Option B. is the correct answer.
Answer: 20-2x/-4
Step-by-step explanation:
To actually solve for y as a number, you need two equations.
For this case move the 2x to the other side, making the equation -4y=20-2x.
Then divide by -4 on each side making the equation y=20-2x/-4.
Answer: C
<u>Step-by-step explanation:</u>
Use the multiplication rule for matrices - Multiply 1st row of first matrix with 1st column of second matrix and find their sum. Repeat for each row and column.
A x B
![\left[\begin{array}{cc}1&5\\-3&4\end{array}\right] \times \left[\begin{array}{cc}2&6\\6&-1\end{array}\right]=\left[\begin{array}{cc}1(2)+5(6)&1(6)+5(-1)\\-3(2)+4(6)&-3(6)+4(-1)\end{array}\right]\\\\\\.\qquad \qquad \qquad \qquad \qquad \quad =\left[\begin{array}{cc}32&1\\18&-22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%265%5C%5C-3%264%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%266%5C%5C6%26-1%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%282%29%2B5%286%29%261%286%29%2B5%28-1%29%5C%5C-3%282%29%2B4%286%29%26-3%286%29%2B4%28-1%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5C.%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cquad%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D32%261%5C%5C18%26-22%5Cend%7Barray%7D%5Cright%5D)
