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AlekseyPX
3 years ago
10

I need help on this question

Mathematics
1 answer:
givi [52]3 years ago
7 0

Answer:

Mexico

Step-by-step explanation:

It’s in Spanish

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A sugar box manufacturing company is accurately making 100 g packets. Suppose a business researcher randomly selects 100 boxes,
irga5000 [103]

Answer:

The kind of error the researcher has done is a;

Type I error

Step-by-step explanation:

When carrying out hypothesis testing in statistical analysis, a type I error is the type of error said to have occurred when a null hypothesis that is true or correct is rejected which is a false positive conclusion

Given that that sugar box manufacturing company makes the boxes to be 100 g accurately, and that the researcher makes non-random or randomly selects packets which are not filled, the mean of the filled packets is expected to be 100 g making the conclusion for rejection of the null hypothesis a false positive rejection

7 0
3 years ago
B. 40 is 160% of what number?
Anton [14]

Answer:

25

Step-by-step explanation:

the question basically translates to

160% x n =40  

a little trick with percents I use is that the word "of" always means multiplication.

n=40/160%=25

6 0
3 years ago
Which equation is equivalent to
Anton [14]

Answer:

m { }^{2}  + 3m + 2 = 0

Step-by-step explanation:

ну где-то тааакккккккккк

8 0
3 years ago
Which expression represents the determinant of A=[-6 -7 -4 -2<br> ]
hram777 [196]
Is that the whole problem?
6 0
3 years ago
Read 2 more answers
in a game of poker, five players are each dealt 5 cards from a 52-card deck. how many ways are there to deal the cards?
Jlenok [28]

The number of ways to deal 5 cards to 5 players from a 52-card deck in a game of poker is (52!)/[(27!)*(5!)^5].

  • Permutations and combinations define nCr as ways of selecting 'r' number of items from 'n' items. 
  • nCr = (n!)/[r!(n-r)!]
  • here we want to deal 5 playing cards to each player.once we deal 5 playing cards to any participant,
  • the playing cards left inside the deck are reduced through five.
  • We deal a total of 25 playing cards, i.e., 5 playing cards to 5 gamers.
  • The number of ways to deal five playing cards to the primary participant is 52C5.The number of approaches to deal 5 playing cards to the second one participant is 47C5.
  • The wide variety of ways to deal 5 cards to the 0.33 player is 42C5.
  • The variety of methods to deal 5 cards to the fourth participant is 37C5.
  • The quantity of ways to deal 5 playing cards to the 5th player is 32C5.
  • the full quantity of methods is the general multiplication.
  • The total number of solutions = 52C5 * 47C5 * 42C5 * 37C5 * 32C5
  • When we simplify, we get (52!)/[(27!)*(5!)^5]. 

To learn more about permutation, visit :

brainly.com/question/1216161

#SPJ4

3 0
1 year ago
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