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LenaWriter [7]
3 years ago
9

Expand the logarithm. log4 (3xyz​)^2

Mathematics
2 answers:
Paladinen [302]3 years ago
8 0

Answer:

Answer is (2log2 + 2log3 + 2logx + 2logy + 2logz)

Step-by-step explanation:

log4(3xyz)²

= log4 + log(3xyz)²

= log4 + 2log(3xyz)

= log(2)² + 2[log3 + logx + logy + logz]

= 2log2 + 2log3 + 2logx + 2logy + 2logz

tangare [24]3 years ago
4 0
2<span>(<span>log4</span><span>(3)</span>+<span>log4</span><span>(x)</span>+<span>log4</span><span>(y)</span>+<span>log4</span><span>(z)</span><span>)</span></span>
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Which exponential function goes through the points (1, 16) and (4, 128)?
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Here is the complete question (attachment).

The function which represent the given points are f(x)=8(2)^{x}

Step-by-step explanation:

We know that a general exponential function is like,y=a(b)^{x}

We can find the answer by hit and trial method by plugging the values of (x,y) coordinates.

Here we are going to solve this with the above general formula.

So as the points are (1,16) then for x=1,\ y=16

Can be arranged in terms of the general equation.

ab^1=16...equation(1) and ab^4=128...equation(2)

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Plugging the values in equation 2.

We have

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Plugging b=2 in equation 1.

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