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Westkost [7]
2 years ago
12

Calculate the quotient and the reminder by dividing f(x)=3x^3 - 5x^2 + x - 2 by g(x) = x + 2 .​

Mathematics
1 answer:
katen-ka-za [31]2 years ago
3 0

Answer:

Step-by-step explanation:

f ( x ) = 3 x ^ { 3 } - 5 x ^ { 2 } + x - 2 g ( x ) = x + 2

Subtract 3x³ from each sides.

-5x^{2}+x-2gx=x+2-3x^{3}

Add 5x² to both sides.

x-2gx=x+2-3x^{3}+5x^{2}

Subtract x from both sides.

-2gx=x+2-3x^{3}+5x^{2}-x

Combine x and -x to get 0.

-2gx=2-3x^{3}+5x^{2}

The equation is in standard form.

\left(-2x\right)g=2+5x^{2}-3x^{3}

Divide both sides by -2x.

\frac{\left(-2x\right)g}{-2x}=\frac{2+5x^{2}-3x^{3}}{-2x}

Dividing bu -2x undoes the multiplication by -2x.

g=\frac{2+5x^{2}-3x^{3}}{-2x}

Divide 2-3x³ +5x² by -2x.

g=\frac{3x^{2}}{2}-\frac{5x}{2}-\frac{1}{x}

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A triangular prism container is full of water of 428 cubic cm. The water is 10 cm deep, what is the base area of the container?
Hatshy [7]
<h3>The base area of triangular prism container is 42.8 cubic centimeter</h3>

<em><u>Solution:</u></em>

<em><u>The volume of triangular prism is given as:</u></em>

v = base\ area \times height

Given that,

A triangular prism container is full of water of 428 cubic cm

The water is 10 cm deep

Therefore,

v = 428 cubic cm

h = 10 cm

<em><u>Substituting the values we get,</u></em>

428 = base\ area \times 10\\\\base\ area = \frac{428}{10}\\\\base\ area = 42.8\ cm^2

Thus the base area of triangular prism container is 42.8 cubic centimeter

3 0
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IrinaVladis [17]

Answer:

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Range:{-2,5,6,23}

The relation is not a function.

Step-by-step explanation:

By definition, a relation is a function if each input value has only one output value.

Given the relation:

(4,23)

(3,-2)

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The domain is the set of the x-coordinates of each ordered pair (You do not need to write 4 twice):

Domain:{-6,3,4}

The range is the set of the y-coordinates of each ordered pair :

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Since the input value 4 has two different output values (23 and 6), the relation is not a function.

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Answer:

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Step-by-step explanation:

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sin(19) = cos(71)

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