Answer:
The number of copper atoms 12.405 ×10²³ atoms.
The number of silver atoms 13.13 ×10²³ atoms.
Beaker B have large number of atoms.
Explanation:
Given data:
In beaker A
Number of moles of copper = 2.06 mol
Number of atoms of copper = ?
In beaker B
Mass of silver = 222 g
Number of atoms of silver = ?
Solution:
For beaker A.
we will solve this problem by using Avogadro number.
The number 6.022×10²³ is called Avogadro number and it is the number of atoms in one mole of substance.
While we have to find the copper atoms in 2.06 moles.
So,
63.546 g = 1 mole = 6.022×10²³ atoms
For 2.06 moles.
2.06 × 6.022×10²³ atoms
The number of copper atoms 12.405 ×10²³ atoms.
For beaker B:
107.87 g = 1 mole = 6.022×10²³ atoms
For 222 g
222 g / 101.87 g/mol = 2.18 moles
2.18 mol × 6.022×10²³ atoms = 13.13 ×10²³ atoms
Answer: 1. AgF + CaCl2 = AgCl + CaF2
2. C2H4 +O2 = CO2 +H2O
3. K2S = K+S
4. O2 + Mg = MgO
5. Mg + AlBr3 = MgBr2 + Al
6.C2H6O + O2= CO2 + H2O
7.Li2SO4 + MgCl2= Li2SO4 + MgCl2
8.HCl + Zn= H2 + ZnCl2
Explanation:
Balance the equation
Write down your given equation.
Write down the number of atoms per each element that you have on each side of the equation.
Always leave hydrogen and oxygen for last.
If you have more than one element left to balance:
Add a coefficient to the single carbon atom on the right of the equation to balance it with the 3 carbon atoms on the left of the equation.
Balance the hydrogen atoms next.
Balance the oxygen atoms.
Explanation:
What's Dis Suppose To Mean ?
