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2 years ago

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Chemistry

1 answer:

Sergeeva-Olga [200]2 years ago

4 0

Answer:

1) Carbon tetrabromide, CBr₄

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements in the compound, which are carbon and bromine

b) Specifying the quantity of the element that has more than one atom per mole of the compound, by making mention of the number in Roman

Here there are four bromine atoms per mole which is mentioned as tetra before the cation is mentioned as bromide or ide for-1 oxidation state for the halogens

c) Indicating the oxidation state of the cation

2) Magnesium oxide, MnO

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements in the compound, which are magnesium and oxygen

b) Specifying the quantity of the elements as one each by leaving out the numbering suffix in the name

c) Indicating the oxidation state of the cation, oxygen, as an oxide with a -2 charge

3) Magnesium Nitrate Mn(NO₃)₂

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements and groups in the compound, which are magnesium and bitrate group

b) Specifying the group by the group name which consists of a means to determine the detailed content of the group

c) Indicating the oxidation state of the group, nitrate, which has with a -1 charge

Explanation:

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What volume of 12 M HCl solution is needed to make 2.5 L of 1.0 M HCI?

Jlenok [28]

Answer:

0.21 L of 12 M HCL

Explanation:

CV=CV

(12)(x)=(1.0)(2.5)

x=0.21

8 0

3 years ago

TiliK225 [7]

Answer: A) Sodium Na and Magnesium Mg

Explanation:

In the period table, you can see that Sodium (group 1) has 11 protons, and Magnesium (group 2) has 12 protons. 11+12=23 protons

5 0

3 years ago

Fill in the blanks below.

Elenna [48]

Answer:

Explanation:

6CO₂ + 6 H₂O ⇄ C₆H₁₂0₆ + 6O₂

This is the chemical equation given .

1. The equation shows a __Chemical equation_______the breaking and forming of chemical bonds that leads to a change in the composition of matter.

2. In the equation, CO₂ is a___reactant_____.

3. In the equation, C₆H₁₂0₆ is a ___product________.

4. In O₂, the type of bond that holds the two oxygen atoms together is a_nonpolar_covalent bond_________.

5. In H₂O, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a__polar_hydrogen bond____.

6. The number of oxygen atoms on the left side of the equation is__equal to_________ the number of oxygen atoms on the right side.

5 0

3 years ago

A bottle containing 415 g of cleaning solution is used to clean hospital equipment. If the cleaning solution has a specific grav

neonofarm [45]

Answer: 483 mL of the cleaning solution are used to clean hospital equipment

Explanation:

The question requires us to calculate the volume, in mL, of solution is used to clean hospital equipment, given that 415g of this solution are used and the specific gravity of the solution is 0.860.

Measurements > Density

Specific gravity is defined as the ratio between the density of a given substance to the density of a reference material, such as water:

$Specific\text{ gravity = }\frac{density\text{ of substance}}{density\text{ of reference substance}}$

The density of a substance is defined as the ratio between the mass and the volume of this substance:

$density=\frac{mass}{volume}$

Considering the reference substance as water and its density as 1.00 g/mL, we can determine the density of the substance which specific gravity is 0.860:

$0.860=\frac{density\text{ of substance}}{1.00g/mL}\rightarrow density\text{ of substance = 0.860g/mL}$

Thus, taking water as the reference substance, we can say that the density of the cleaning solution is 0.860 g/mL.

Now that we know the density of the cleaning solution (0.860 g/mL) and the mass of solution that is used to clean hospital equipment (415g), we can calculate the volume of solution that is used to clean the equipment:

$\begin{gathered} density=\frac{mass}{volume}\rightarrow volume=\frac{mass}{density} \\ \\ volume=\frac{415g}{0.860g/mL}=483mL \end{gathered}$

Therefore, 483 mL of the cleaning solution are used to clean hospital equipment.

6 0

1 year ago

The oxidation of Cu₂O(s) to CuO(s) is an exothermic process:

Alex73 [517]

Answer:

w = 7376.6 J

Explanation:

To calculate the work done in the system, we need first to calculate the number of moles of all compounds.

The following expression, that comes from the 1° law of thermodynamic, will help you to get the work:

w = ΔnRT

Where:

Δn: difference in the number of moles between products and reactants

R: constant universal of gases (8.314 J / mol K)

T: Temperature in Kelvin.

As we are doing this reaction in STP, then the Pressure is 1 atm, and temperature is 0 °C or 273 K.

Now, we already have the moles of Cu₂O, let's see, according to the balanced reaction, how many moles we should have of O₂ and CuO.

If 1 mole of O₂ reacts with 2 moles of Cu₂O then 6.5 moles of Cu₂O will be:

moles O₂ = 6.5 moles Cu₂O * (1 mole O₂/2 moles Cu₂O) = 3.25 moles O₂

If 2 moles of Cu₂O produces 4 moles of CuO, then 6.5 moles will be:

moles CuO = 6.5 moles Cu₂O*(4 moles CuO/2 moles Cu₂O) = 13 moles CuO

Now that we have the moles, let's calculate the value of Δn.

Δn = moles product - moles reactants

Δn = 13 - (6.5 + 3.25) = 3.25 moles

Now, we can calculate the work done in the system:

w = 3.25 * (8.314 * 273)

Hope this helps

8 0

3 years ago