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tankabanditka [31]
2 years ago
5

Your paragraph containing

Chemistry
1 answer:
Sergeeva-Olga [200]2 years ago
4 0

Answer:

1) Carbon tetrabromide, CBr₄

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements in the compound, which are carbon and bromine

b) Specifying the quantity of the element that has more than one atom per mole of the compound, by making mention of the number in Roman

Here there are four bromine atoms per mole which is mentioned as tetra before the cation is mentioned as bromide or ide for-1 oxidation state for  the halogens

c) Indicating the oxidation state of the cation

2) Magnesium oxide, MnO

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements in the compound, which are magnesium and oxygen

b) Specifying the quantity of the elements as one each by leaving out the numbering suffix in the name

c) Indicating the oxidation state of the cation, oxygen, as an oxide with a -2 charge

3) Magnesium Nitrate Mn(NO₃)₂

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements and groups in the compound, which are magnesium and bitrate group

b) Specifying the group by the group name which consists of a means to determine the detailed content of the group

c) Indicating the oxidation state of the group, nitrate, which has  with a -1 charge

Explanation:

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Because oxygen is more electronegative than hydrogen, the water molecule isA. hydrophobicB. organicC. polarD. ionic
Strike441 [17]

Because oxygen is more electronegative than hydrogen, the water molecule is polar.

6 0
2 years ago
1. How many MOLECULES are contained in 80.0 grams of sodium hydroxide?
Anna11 [10]

Answer:

2 molecules

Explanation:

In 80 grams there will be 2 molecules of NaOH, so mass of Sodium would be 23 x 2 = 46g.

6 0
3 years ago
How does a balanced chemical equation satisfy the law of conservation of mass
ELEN [110]
Every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. ... When an equal number of atoms of an element is present on both sides of a chemical equation, the equation is balanced.
4 0
2 years ago
Identify the hybridization of each carbon atom for the molecule above
ipn [44]

Carbons starting from the left end:

  1. sp²
  2. sp²
  3. sp²
  4. sp
  5. sp

Refer to the sketch attached.

<h3>Explanation</h3>

The hybridization of a carbon atom depends on the number of electron domains that it has.

Each chemical bond counts as one single electron domain. This is the case for all chemical bonds: single, double, or triple. Each lone pair also counts as one electron domain. However, lone pairs are seldom seen on carbon atoms.

Each carbon atom has four valence electrons. It can form up to four chemical bonds. As a result, a carbon atom can have up to four electron domains. It has a minimum of two electron domains, with either two double bonds or one single bond and one triple bond.

  • A carbon atom with four electron domains is sp³ hybridized;
  • A carbon atom with three electron domains is sp² hybridized;
  • A carbon atom with two electron domains is sp hybridized.

Starting from the left end (H₂C=CH-) of the molecule:

  • The first carbon has three electron domains: two C-H single bonds and one C=C double bond; It is sp² hybridized.
  • The second carbon has three electron domains: one C-H single bond, one C-C single bond, and one C=C double bond; it is sp² hybridized.
  • The third carbon has three electron domains: two C-C single bonds and one C=O double bond; it is sp² hybridized.
  • The fourth carbon has two electron domains: one C-C single bond and one C≡C triple bond; it is sp hybridized.
  • The fifth carbon has two electron domains: one C-H single bond and one C≡C triple bond; it is sp hybridized.

8 0
3 years ago
What mass of oxygen is needed to combust and produced 6.4 moles of carbon dioxide gas?
N76 [4]
You have already gotten the balanced equation. And the ratio of mol number of reactants and production is the ratio of coefficient. So there is 6.4/8*11=8.8 mol oxygen needed. The mass is 8.8*32=281.6 g.
6 0
3 years ago
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