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asambeis [7]
3 years ago
15

Lists how many valence electrons are shared, gained, or lost by each atom of the 6 compounds?      

Chemistry
1 answer:
Blababa [14]3 years ago
6 0
<span>The number of electrons in an atom's outermost valence shell governs its bonding behavior.

In N</span>₂, three electrons are being shared by each nitrogen atom, making a total of 6 shared electrons.

In CCl₄, 4 electrons are being shared by each carbon atom and 1 electron is being shared by each chlorine atom

In SiO₂, 4 electrons are being shared by each silicon atom and 2 electrons are being shared by each oxygen atom.

In AlCl₃, 3 electrons are being shared by each aluminum atom and 1 electron is being shared by each Cl atom

In CaCl₂, 2 electrons are lost by the calcium atom and 1 electron is gained by each chlorine atom

In LiBr, 1 electron is lost by the lithium atom and 1 electron is gained by the bromine atom
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8 0
3 years ago
a sample of an oxide of antimony (sb) contain 19.75 g of antimony combine with 6.5 g of oxygen . what is the simplest formula fo
frez [133]

Explanation:

The given data is as follows.

      Mass of antimony = 19.75 g

      Molar mass of Sb = 121.76 g/mol

Therefore, calculate number of moles of Sb as follows.

                    Moles of Sb = \frac{mass}{\text{molar mass}}

                                         = \frac{19.75 g}{121.76 g/mol}

                                         = 0.162 mol

Mass of oxygen given is 6.5 g and molar mass of oxygen is 16 g/mol. Hence, moles of oxygen will be calculated as follows.

           Moles of oxygen = \frac{mass}{\text{molar mass}}

                                         = \frac{6.5 g}{16 g/mol}

                                         = 0.406 mol

Hence, ratio of moles of Sb and O will be as follows

                          Sb : O

                      \frac{0.162}{0.162} : \frac{0.406}{0.162}

                           1 : 2.5

We multiply both the ratio by 2 in order to get a whole number. Therefore, the ratio will be 2 : 5.

Thus, we can conclude that the empirical formula of the given oxide is Sb_{2}O_{5}.

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Answer:

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