Answer:
Step-by-step explanation:
Given 
y = 3x + 2
Comparing with y = mx + c
slope (m) = 3
y-intercept (c) = 2
 
        
                    
             
        
        
        
I think the answer is 62 cm2
 
        
             
        
        
        
I’m not sure if this is a question, but yes, i like to use “PEMDAS”. 
Parentheses, exponents, multiply, divide, add, subtract. 
You always go in order from left to right!
        
             
        
        
        
Answer:Area of part 1:
A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2
Area of part 2:
A2=length*width=(8+2)*1=10 ft2
Area of part 3:
A3=length*width=8*2=16 ft2
Total shaded area : A1+A2+A3=41 ft2
Total area of the reactangle : A=16*8=128 ft2
Total area of the nonshaded region : 128-41=87 ft2
Step-by-step explanation: Plz make brainliest
 
        
             
        
        
        
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water 
Using the formula, 
v = fλ 
∴ λ = v/f
Where v is the velocity 
f is the frequency 
and λ is the wavelength 
For the first wave 
f = 20 waves/sec 
Then, 
λ₁ = v/20 
For the second wave 
f = 16,000 waves/sec 
λ₂ = v/16000
Then, 
The factor by which the first sound wave is longer than the second sound wave is 
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485 
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