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3 years ago

Need help ASAP.picture provides question

Mathematics

1 answer:

OLga [1]3 years ago

5 0

Answer:

p=12-7/x

Step-by-step explanation:

thats what p(2)is

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16 5x=31 what does x equal

liraira [26]

If you mean 165x = 31 , X = <span>0.19871794871
if you mean 16*5x = 31 , X = .3875
if you mean 16+5x=31 , X = 3
If you mean 16 -5x=31 , X = -3
Hope one of these is correct.</span>

6 0

3 years ago

Helps pls help pls thank you so much

Juliette [100K]

Answer:

Increases, same, increases, decreases

Step-by-step explanation:

I mean just look at the graph

7 0

3 years ago

Find the value of x and y in the following figure where ABCD is a parallelogram<br><br>

asambeis [7]

Answer:

x = 3

y = 2

Step-by-step explanation:

Diagonals of a parallelogram bisect each other into two equal segments. Therefore:

3x - 1 = 2(x + 1)

Solve for x

3x - 1 = 2x + 2

Collect like terms

3x - 2x = 1 + 2

x = 3

Also:

5y + 1 = 6y - 1

Collect like terms

5y - 6y = -1 - 1

-y = -2

Divide both sides by -1

y = -2/-1

y = 2

5 0

3 years ago

A guitar string is plucked at a distance of 0.6 centimeters above its resting position and then released, causing vibration. The

liubo4ka [24]

Answer:

The equation that represents the motion of the string is given by:

$y =Ae^{-kt}\cos(2\pi ft)$ .....[1] where t represents the time in second.

Given that: A = 0.6 cm (distance above its resting position) , k = 1.8(damping constant) and frequency(f) = 105 cycles per second.

Substitute the given values in [1] we get;

$y =0.6e^{-1.8t}\cos(2\pi 105t)$

$y =0.6e^{-1.8t}\cos(210\pi t)$

(a)

The trigonometric function that models the motion of the string is given by:

$y =0.6e^{-1.8t}\cos(210\pi t)$

(b)

Determine the amount of time t that it takes the string to be damped so that $-0.24\leq y \leq0.24$

Using graphing calculator for the equation

$y =0.6e^{-1.8x}\cos(210\pi x)$

let x = t (time in sec)

Graph as shown below in the attachment:

we get:

the amount of time t that it takes the string to be damped so that $-0.24\leq y \leq0.24$ is, 0.5 sec

4 0

3 years ago

Can someone please help me with this problem?! 15points

xxMikexx [17]

I’m fairly certain it is 70 , or option 4 :))

3 0

3 years ago