Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph
To Find : Maximum profit , breakeven point , profit interval
Solution:
The maximum profit the florist will earn from selling celebration bouquets is $ 675
peak of y from Graph
The florist will break-even after Selling 20 one-dollar decreases.
at breakeven
Break even is the point where the profit p(x) becomes 0
The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).
after 20 , P(x) is - ve
Answer:
Replace
F
(
x
)
with
y
.
y
=
9
x
Interchange the variables.
x
=
9
y
Solve for
y
.
Tap for more steps...
y
=
x
9
Solve for
y
and replace with
F
−
1
(
x
)
.
Tap for more steps...
F
−
1
(
x
)
=
x
9
Step-by-step explanation:
27-9r
explaintion:
3•9+3•-3r
27+3•-3r=
27-9r
Leg * /2 = hypotenuse
Hypotenuse divided by /2 = leg
12 divided by /2
Rationalize denominator:
12 * /2 divided by by /2 * /2
Simplify denominator:
12 * /2 divided by 2
Simplify:
6 * /2 or 4.24
Both x and y because it’s a 45-45-90 triangle
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