The amount of resistance, y, in a circuit varies inversely to the current, x, in the circuit. When 10 ohms of resistance are use
1 answer:
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To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
[recall 
or 20(x+5) if you wish.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
Answer:
Yes, I agree
Step-by-step explanation:
For the cubic function
A cubic function is represented as:
A cubic function may have 1, 2 or 3 x intercepts. This is shown below
For 3 x intercepts
Equate y to 0
Expand
Express as difference of two squares
<em>x = 0 or 1 or -1</em>
For 2 x intercepts
Equate y to 0
Expand
<em>x= 5 or x = -7</em>
For 1 x intercept
Equate y to 0
Take cube roots of both sides
It has been shown above that a cubic function may have 1, 2 or 3.
So, I agree to the statement
For the quadratic function
A quadratic function will not have any x intercept when the function can not be factorized;
E.g.
<em>The above function has no x intercept.</em>
A quadratic function will have at least 1 x intercept when the function can be factorized;
E.g.
Equate y to 0
Expand
We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)
Hence, I agree to both statement