Answer:
15 ml
Explanation:
Volume = mass / density.
So our answer is 15 / 3 = 15 mL
The computation for molarity is:
(x) (0.175 L) = 0.0358 g / 598 g/mol
x = 0.000342093 M
Whereas the osmotic pressure calculation:
pi = iMRT
pi = (1) (0.000342093 mol/L) (0.08206 L atm / mol K) (298 K)
pi = 0.0083655 atm
Converting the answer to torr, will give us:
0.0083655 atm times (760 torr/atm) = 6.35778 torr
which rounds off to 6.36 torr
<span>maximizes the surface area.</span>
Answer:
60.88%
Explanation:
The <em>formula for cerium carbonate</em> is Ce₂(CO₃)₃.
Let's <u>assume we have 1 mol of cerium carbonate</u>. The total mass would be equal to the molar mass of Ce₂(CO₃)₃, 460.25 g/mol.
Out of those 460.25 g, the mass <u>corresponding to cerium would be</u>:
- 2 * Molar mass of Ce = 2 * 140.11 g/mol = 280.22 g
Now we can <u>calculate the percentage by mass of cerium</u>:
- % mass = 280.22 / 460.25 * 100% = 60.88%
We should indicate first and foremost the assumption of ideal gas behavior so that we can use the ideal gas equation written below:
PV = nRT
For this problem,let's solve for V. Rearranging the equation,
V = nRT/P
Substituting the values,
V = (1 mol)(0.0821 L-atm/mol-K)(30 + 273 K)/1.2 atm
<em>V = 20.73 L of N₂ gas</em>
