A line of best fit is drawn for the set of points shown on the graph. Which point is an approximate for x=30 from the line of be
st fit?
(23,30)
(30,38)
(44,30)
(30,72)
(23,30)
(30,38)
(44,30)
(30,72)
2 answers:
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A 33 gram sample has k value of .1124
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)
See attached graphic:
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.1124/days
Half-Life = <span> <span> <span> 6.1667882562 </span> </span> </span> days
Source:
http://www.1728.org/halflif2.htm
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)
See attached graphic:
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.1124/days
Half-Life = <span> <span> <span> 6.1667882562 </span> </span> </span> days
Source:
http://www.1728.org/halflif2.htm
Answer:
La situación está representada por el siguiente sistema:
Donde:
- Cantidad de rosas vendidas semanalmente.
- Ganancia semanal, medida en dólares.
Step-by-step explanation:
De acuerdo con el enunciado, Nita gana una cantidad fija cada semana por pasear al perro de su vecino, con un monto de $ 20, mientras que gana en función de la cantidad de rosas a vender, con un valor unitario de $ 2. Si ella desea ganar al menos $ 50, por tanto, se requiere construir el siguiente sistema, conformado por una ecuación y una inecuación:
(1)
(2)
Donde:
- Cantidad de rosas vendidas semanalmente.
- Ganancia semanal, medida en dólares.
Answer:
Step-by-step explanation:
Using the formula for the exponential decay that is , we have N=
,
and k=0.1374.
Thus, becomes
Taking log on both sides, we get