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Gre4nikov [31]
2 years ago
7

Identify the indicated angles as Adjacent, vertical, linear, or complimentary

Mathematics
1 answer:
Vesnalui [34]2 years ago
8 0
This is an adjacent angle. Both the angles have an common side and a common vertex. Hope this helped :)
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Aya and Kendra want to estimate the height of a tree. On a sunny day, Aya measures Kendra's shadow as 3 meters long, and Kendra
densk [106]

Answer:

tree=4.5 meters tall

Step-by-step explanation:

1.5*3=4.5

6 0
2 years ago
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Explain how 7 x 20 is similar to 7 x 2,000
zmey [24]
The answer will be similar as 7x20=140 and 7x2000=14000, the answers are the same but x100 as 140x100=14000
20x100=2000
6 0
3 years ago
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The list shows the number of contacts six people each have stored in the their cell phone: 68, 72, 77, 64, 69, 76. What is the m
sergij07 [2.7K]
The correct answer is C- 4
8 0
3 years ago
Does the data in the table represent a direct variation or an inverse variation? Write an equation to model the data in the tabl
MakcuM [25]

The equation for the direct variation is y= kx (where k is contant of variation.)

This equation represent that if x will increase then y will also increase because it's k times x.

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By this equation if x will increase then y will decrease and vice versa.

The given data is :

x: 2 4 8 12

y: 4 2 1 2/3

Notice as x is increasing then y is decreasing. Like x has increased from 2 to 4 then y is decresing from 4 to 2 and so on.

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7 0
3 years ago
Given that f(x) = 19x2 + 152, solve the equation f(x) = 0
telo118 [61]

<em><u>Option A</u></em>

<em><u>The solution is:</u></em>

x = \pm 2i \sqrt{2}

<em><u>Solution:</u></em>

f(x) = 19x^2+152

We have to solve the equation f(x) = 0

Let f(x) = 0

0=19x^2+152

Solve the above equation

19x^2 + 152 = 0

\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8

Take square root on both sides

x =  \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}

Thus the solution is found

5 0
3 years ago
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