Answer:
The plasma membrane is made up by a phospholipid bilayer with embedded proteins that separates the internal contents of the cell from its surrounding environment. Only relatively small, non- polar materials can easily move through the lipid bilayer of the plasma membrane.
Explanation:
A antigens, B antigens, and Rh
Answer:
Sea floor spreading-> <u><em>Oceanic ridge and Magma pushing two plates apart</em></u>
Continental drift-> <u><em>Concept of pangaea and Oceanic plates sliding under continental crust</em></u>
Explanation:
Due to the divergent plate movement, the magma come out to the surface, forming the mid oceanic ridge and this separation of plates on the sea floor is known as the sea floor spreading. The magma here pushes the two plates to move apart because of the convection current that generates in the mantle. One example of mid oceanic ridge is the Mid-Atlantic Ridge.
Continental drift refers to the slow and gradual movement of the lithospheric plates over the viscous asthenosphere layer. This motion of continents takes place because of the plate tectonic movement. Due to this plate motion, the denser plate gets subducts beneath the less denser plates. For example, the oceanic crust when collides with a continental crust, it gets subducted because of its higher density. The great supercontinent "pangaea" also formed and separated due to this plate motion.
Answer:
2.275% of this population has a diastolic blood pressure less than 60 mmHg
Explanation:
Hello!
Yo have the distribution of the diastolic blood pressure in a certain population. Be X: diastolic blood pressure of an individual, X~N(μ;δ²)
Where
μ= 82mmHg
δ=11 mmHg
You need to calculate the probability of an individual of this population having less than 60mmHg diastolic blood pressure.
Symbolically:
P(X<60)
To obtain the value of probability you need to standardize the value of diastolic pressure so that you can obtain it from the standard normal distribution. The way to standardize the value is to subtract the mean and divide by the standard deviation
Z= (X-μ)/δ~N(0;1)
P(Z<(60-82)/11)
P(Z<-2)= 0.02275
I hope it helps!
